Separate CountYou are given a string as input from the user which contains the brackets {}() []. You have to writea program that prints the count of the brackets (, ), {, }, [, ] separately in the given order.Refer to sample output.Sample Case:Input: ({)[[)]({[])Output:(->2) -> 3{-> 2}->2[ -> 3]->2

The string toCharArray() method converts the given string into a sequence of characters.

Answered: Separate Count You are given a string…

Computer Networking: A Top-Down Approach (7th Edition)

7th Edition

ISBN:9780133594140

Author:James Kurose, Keith Ross

Publisher:James Kurose, Keith Ross

Chapter1: Computer Networks And The Internet

Section: Chapter Questions

Problem R1RQ: What is the difference between a host and an end system? List several different types of end...

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// MichiganCities.cpp - This program prints a message for invalid cities in Michigan. // Input: Interactive // Output: Error message or nothing #include <iostream> #include <string> using namespace std; int main() { // Declare variables string inCity; // name of city to look up in array const int NUM_CITIES = 10; // Initialized array of cities string citiesInMichigan[] = {"Acme", "Albion", "Detroit", "Watervliet", "Coloma", "Saginaw", "Richland", "Glenn", "Midland", "Brooklyn"}; bool foundIt = false; // Flag variable int x; // Loop control variable // Get user input cout << "Enter name of city: "; cin >> inCity; // Write your loop here // Write your test statement here to see if there is // a match. Set the flag to true if city is found. // Test to see if city was not found to determine if // "Not a city in Michigan" message should be printed.…
#include <iostream>#include <string.h>using namespace std;int index1(char *T,char *P){int t=0,p=0,i,j,r;t = strlen(T);p = strlen(P);i=0;int max = t - p + 1;while(i<max){for(j=0;j<p;j++){if(P[j]==T[i+j]){r = i;break;}else r = -1;}i++;}return r;} int main(){ int l;char c[100];char d[100];cout<<"Enter First String\n"; cin>>c;cout<<"Enter Second String\n";cin>>d;l = index1(c,d);cout<<l; return 0;} Note: Remove Funcation
static List<String> findWinners(String pattern, int minLength, boolean even, Stream<String> stream) This function will receive a stream of strings and it will return a sorted list of strings that meet all of the following criteria: They must contain the pattern The strings length must be equal to or greater than the min length number The strings length must be an even or odd number This Function must take no longer 10000 milliseconds to return. pattern - A pattern that all the strings in the list returned must containminLength - The length that all the strings in the list returned must be equal to or greater thaneven - True if even false if odd. Denotes a condition that all the strings in the list returned must have a length that is even or odd.stream - A stream of strings to be filteredreturn - A list of strings that meets the criteria outlined above sorted by their length from small to large
Scala Programming: Given string str, write a Scala program to create a new string where "Scala " is added to the front of a given string. If the string already begins with "Scala", return the string unchanged. Otherwise, return the string after adding "Scala ". Test the function for two strings "Scala Programming" and "Programming" inside the main method.
#include<bits/stdc++.h>using namespace std;bool isPalindrome(string &s){ int start=0; int end=s.length()-1; while(start<=end) { if(s[start]!=s[end]) { return false; } start++; end--; } return true;}int main(){ string s; cout<<"ENTER STRING:"; getline(cin,s); int n=s.length(); bool flag=true; for(int i=1;i<n;i++) { string lowerHalf=s.substr(0,i); string upperHalf=s.substr(i,n-i); if(isPalindrome(lowerHalf) && isPalindrome(upperHalf)) { flag=false; cout<<"String A is:"<<lowerHalf<<"\n"; cout<<"String B is:"<<upperHalf<<"\n"; break; } } if(flag) { cout<<"NO\n"; } return 0;} change to stdio.h string.h
Exercise2: Thestrcmp(string1,string2)function comparesstring1to string2. It is a value returning function that returns a negative integer if string1 < string2, 0 if string1 == string2, and a positive integer if string1 > string2. Write a program that reads two names (last name first followed by a comma followed by the first name) and then prints them in alphabetical order. The two names should be stored in separate character arrays holding a maximum of 25 characters each. Use the strcmp() func- tion to make the comparison of the two names. Remember that 'a' < 'b', 'b' < 'c', etc. Be sure to include the proper header file to use strcmp(). Sample Run 1: Please input the first name Brown, George Please input the second name Adams, Sally The names are as follows: Adams, SallyBrown, George Sample Run 2: Please input the first name Brown, George Please input the second name Brown, George The names are as follows: Brown, GeorgeBrown, GeorgeThe names are the same
#include <iostream>#include <iomanip>#include <string>using namespace std;struct menuItemType{string menuItem;double menuPrice;};void getData(menuItemType menuList[]);void showMenu(menuItemType menuList[] , int n);void printCheck(menuItemType menuList[], int menu_order[], int n);int main(){const int item = 8;menuItemType menuList[item];int menu_order[item] ={0};int choice =0;int count =0;bool order = true;getData(menuList);showMenu(menuList,item);while(order){cout<<"Enter the choice for the order or press 0 to exit"<<endl;cin>>choice;if(choice>0 && choice<=item){menu_order[choice-1]+=1;}else{order=false;}}printCheck(menuList,menu_order,item);return 0;}void getData(menuItemType menuList[]){menuItemType plainEgg;menuItemType baconEgg;menuItemType muffin;menuItemType frenchToast;menuItemType fruitBasket;menuItemType cereal;menuItemType coffee;menuItemType tea;plainEgg.menuItem = "Plain Egg";plainEgg.menuPrice = 1.45;baconEgg.menuItem =…
C++ Nested loops: Print seats. Given numRows and numColumns, print a list of all seats in a theater. Rows are numbered, columns lettered, as in 1A or 3E. Print a space after each seat, including after the last. Ex: numRows = 2 and numColumns = 3 prints:1A 1B 1C 2A 2B 2C #include <iostream>using namespace std; int main() { int numRows; int numColumns; int currentRow; int currentColumn; char currentColumnLetter; cin >> numRows; cin >> numColumns; /* Your solution goes here */ cout << endl; return 0;}
#include <stdio.h>#include <limits.h> int findMissingUtil(int arr[], int low, int high, int diff){ if (high <= low)return INT_MAX; int mid = low + (high - low)/2; if (arr[mid+1] - arr[mid] != diff)return (arr[mid] + diff); if (mid > 0 && arr[mid] - arr[mid-1] != diff)return (arr[mid-1] + diff); if (arr[mid] == arr[0] + mid*diff)return findMissingUtil(arr, mid+1, high, diff); return findMissingUtil(arr, low, mid-1, diff);} int findMissing(int arr[], int n){int diff = (arr[n-1] - arr[0])/n; return findMissingUtil(arr, 0, n-1,diff);} int main(){int arr[] = {120001, 120013, 120025, 120037, 120049, 120061,120085,120097,120109,120121};int n = sizeof(arr)/sizeof(arr[0]);printf("The missing element is %d", findMissing(arr, n));return 0;} ______________________________________________________________________________ Convert the code above into Pseudocode

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