vector mystery (string word) { vector result; if (word. length() <= 1) { } result.push_back (word); return result; } for (int i = 0; i < word. length(); i++) { string shorter_word = word.substr(0, i) + word.substr(i + 1); vector shorter_mystery = mystery (shorter_word); for (int j = 0; j < shorter_mystery.size(); j++) { } string longer_word = word [i] + shorter_mystery [j]; result.push_back (longer_word); } return result; The code enters a situation where it keeps calling itself without ever ending. The code returns the number of characters in a string. The code generates all permutations of the characters in a string. The code always extracts the first character from the entered string and places the remaining string as a suffix.
vector mystery (string word) { vector result; if (word. length() <= 1) { } result.push_back (word); return result; } for (int i = 0; i < word. length(); i++) { string shorter_word = word.substr(0, i) + word.substr(i + 1); vector shorter_mystery = mystery (shorter_word); for (int j = 0; j < shorter_mystery.size(); j++) { } string longer_word = word [i] + shorter_mystery [j]; result.push_back (longer_word); } return result; The code enters a situation where it keeps calling itself without ever ending. The code returns the number of characters in a string. The code generates all permutations of the characters in a string. The code always extracts the first character from the entered string and places the remaining string as a suffix.
Database System Concepts
7th Edition
ISBN:9780078022159
Author:Abraham Silberschatz Professor, Henry F. Korth, S. Sudarshan
Publisher:Abraham Silberschatz Professor, Henry F. Korth, S. Sudarshan
Chapter1: Introduction
Section: Chapter Questions
Problem 1PE
Related questions
Question
In C++
![8
vector<string> mystery (string word)
{
vector<string> result;
if (word. length() <= 1)
{
}
result.push_back(word);
return result;
}
for (int i = 0; i < word. length(); i++)
{
string shorter_word = word.substr(0, 1)
+ word.substr(i + 1);
vector<string> shorter_mystery = mystery (shorter_word);
for (int j = 0; j < shorter_mystery.size(); j++)
{
}
string longer_word = word [i] + shorter_mystery [j];
result.push_back (longer_word);
}
return result;
The code enters a situation where it keeps calling itself without ever ending.
The code returns the number of characters in a string.
The code generates all permutations of the characters in a string.
The code always extracts the first character from the entered string and places
the remaining string as a suffix.](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F115bc08a-05f9-46c8-bfbd-3937dbcb6bf8%2F62478225-f69d-4188-aa5d-35544b630210%2Fbkqmmy_processed.jpeg&w=3840&q=75)
Transcribed Image Text:8
vector<string> mystery (string word)
{
vector<string> result;
if (word. length() <= 1)
{
}
result.push_back(word);
return result;
}
for (int i = 0; i < word. length(); i++)
{
string shorter_word = word.substr(0, 1)
+ word.substr(i + 1);
vector<string> shorter_mystery = mystery (shorter_word);
for (int j = 0; j < shorter_mystery.size(); j++)
{
}
string longer_word = word [i] + shorter_mystery [j];
result.push_back (longer_word);
}
return result;
The code enters a situation where it keeps calling itself without ever ending.
The code returns the number of characters in a string.
The code generates all permutations of the characters in a string.
The code always extracts the first character from the entered string and places
the remaining string as a suffix.
![What does this function do?
vector<string> mystery (string word)
vector<string> result;
if (word. length() <= 1)
{
{
}
result.push_back(word);
return result;
}
for (int i = 0; i < word. length(); i++)
{
string shorter_word = word.substr(0, i)
+ word.substr(i + 1);
vector<string> shorter_mystery = mystery (shorter_word);
for (int j = 0; j < shorter_mystery.size(); j++)
{
}
string longer_word = word [i] + shorter_mystery [j];
result.push_back (longer_word);
}
return result;
The code enters a situation where it keeps calling itself without ever ending.
The code returns the number of characters in a string.
The code generates all permutations of the characters in a string.
The code always extracts the first character from the entered string and places](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F115bc08a-05f9-46c8-bfbd-3937dbcb6bf8%2F62478225-f69d-4188-aa5d-35544b630210%2Fjd9cw7_processed.jpeg&w=3840&q=75)
Transcribed Image Text:What does this function do?
vector<string> mystery (string word)
vector<string> result;
if (word. length() <= 1)
{
{
}
result.push_back(word);
return result;
}
for (int i = 0; i < word. length(); i++)
{
string shorter_word = word.substr(0, i)
+ word.substr(i + 1);
vector<string> shorter_mystery = mystery (shorter_word);
for (int j = 0; j < shorter_mystery.size(); j++)
{
}
string longer_word = word [i] + shorter_mystery [j];
result.push_back (longer_word);
}
return result;
The code enters a situation where it keeps calling itself without ever ending.
The code returns the number of characters in a string.
The code generates all permutations of the characters in a string.
The code always extracts the first character from the entered string and places
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