vector mystery (string word) { vector result; if (word. length() <= 1) { } result.push_back (word); return result; } for (int i = 0; i < word. length(); i++) { string shorter_word = word.substr(0, i) + word.substr(i + 1); vector shorter_mystery = mystery (shorter_word); for (int j = 0; j < shorter_mystery.size(); j++) { } string longer_word = word [i] + shorter_mystery [j]; result.push_back (longer_word); } return result; The code enters a situation where it keeps calling itself without ever ending. The code returns the number of characters in a string. The code generates all permutations of the characters in a string. The code always extracts the first character from the entered string and places the remaining string as a suffix.
vector mystery (string word) { vector result; if (word. length() <= 1) { } result.push_back (word); return result; } for (int i = 0; i < word. length(); i++) { string shorter_word = word.substr(0, i) + word.substr(i + 1); vector shorter_mystery = mystery (shorter_word); for (int j = 0; j < shorter_mystery.size(); j++) { } string longer_word = word [i] + shorter_mystery [j]; result.push_back (longer_word); } return result; The code enters a situation where it keeps calling itself without ever ending. The code returns the number of characters in a string. The code generates all permutations of the characters in a string. The code always extracts the first character from the entered string and places the remaining string as a suffix.
Database System Concepts
7th Edition
ISBN:9780078022159
Author:Abraham Silberschatz Professor, Henry F. Korth, S. Sudarshan
Publisher:Abraham Silberschatz Professor, Henry F. Korth, S. Sudarshan
Chapter1: Introduction
Section: Chapter Questions
Problem 1PE
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