Given an unordered_set names, compare the code segments if (names.count("Fred") and == } 1) { cout << "found" << endl; } for (auto iter = names.begin(); iter != names.end(); iter++) { if (*iter == "Fred") { cout << "found" << endl; } Which statement about these code segments is true? O They have the same result, but the first one is more efficient. O They have the same result, but the second one is more efficient. They have the same efficiency when "Fred" is at the end of the set and different results when it is near the front. O They have the same result and both are equally efficient.

Database System Concepts
7th Edition
ISBN:9780078022159
Author:Abraham Silberschatz Professor, Henry F. Korth, S. Sudarshan
Publisher:Abraham Silberschatz Professor, Henry F. Korth, S. Sudarshan
Chapter1: Introduction
Section: Chapter Questions
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Given an unordered_set names, compare the code segments
if (names.count("Fred")
and
}
==
1) { cout << "found" << endl; }
for (auto iter = names.begin(); iter != names.end(); iter++)
{
if (*iter "Fred") { cout << "found" << endl; }
Which statement about these code segments is true?
O They have the same result, but the first one is more efficient.
They have the same result, but the second one is more efficient.
They have the same efficiency when "Fred" is at the end of the set and different results when it
is near the front.
O They have the same result and both are equally efficient.
Transcribed Image Text:Given an unordered_set names, compare the code segments if (names.count("Fred") and } == 1) { cout << "found" << endl; } for (auto iter = names.begin(); iter != names.end(); iter++) { if (*iter "Fred") { cout << "found" << endl; } Which statement about these code segments is true? O They have the same result, but the first one is more efficient. They have the same result, but the second one is more efficient. They have the same efficiency when "Fred" is at the end of the set and different results when it is near the front. O They have the same result and both are equally efficient.
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