Using the code source screenshot (C++) explain in depth what each line of code does.

Database System Concepts
7th Edition
ISBN:9780078022159
Author:Abraham Silberschatz Professor, Henry F. Korth, S. Sudarshan
Publisher:Abraham Silberschatz Professor, Henry F. Korth, S. Sudarshan
Chapter1: Introduction
Section: Chapter Questions
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Using the code source screenshot (C++) explain in depth what each line of code does. 

 

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#include <iostream>
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using namespace std;
9.
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struct node {
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int info;
struct node *left;
struct node *right;
};
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struct node *generateNode(int value) {
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struct node *temp = (struct node*) malloc(sizeof(struct node));
temp->info = value;
temp->left = temp->right = NULL;
return temp;
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}
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void preorder(struct node *root) {
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if (root != NULL) {
cout << root->info < " ";
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preorder(root->left);
preorder(root->right);
}
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}
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struct node* addNode(struct node* node, int value) {
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if (node == NULL)
return generateNode(value);
if (value < node->info)
node->left = addNode(node->left, value);
else if (value > node->info)
node->right =
return node;
}
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addNode(node->right, value);
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int main() {
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struct node *root = NULL;
root = addNode(root, 6);
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addNode(root, 2);
addNode(root, 1);
addNode(root, 4);
addNode(root, 3);
addNode(root, 5);
addNode(root, 8);
addNode(root, 7);
addNode(root, 9);
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cout << "\nThe pre-order tree traversal of the nodes’ values is: ";
preorder(root);
cout << "\n" << endl;
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return 0;
}
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Transcribed Image Text:7 #include <iostream> 8 using namespace std; 9. 10 struct node { 11 12 int info; struct node *left; struct node *right; }; 13 14 15 16 17 struct node *generateNode(int value) { 18 struct node *temp = (struct node*) malloc(sizeof(struct node)); temp->info = value; temp->left = temp->right = NULL; return temp; 19 20 21 22 23 24 } 25 26 void preorder(struct node *root) { 27 if (root != NULL) { cout << root->info < " "; 28 29 preorder(root->left); preorder(root->right); } 30 31 32 33 } 34 35 struct node* addNode(struct node* node, int value) { 36 if (node == NULL) return generateNode(value); if (value < node->info) node->left = addNode(node->left, value); else if (value > node->info) node->right = return node; } 37 38 39 40 41 42 addNode(node->right, value); 43 44 45 46 int main() { 47 48 struct node *root = NULL; root = addNode(root, 6); 49 50 addNode(root, 2); addNode(root, 1); addNode(root, 4); addNode(root, 3); addNode(root, 5); addNode(root, 8); addNode(root, 7); addNode(root, 9); 51 52 53 54 55 56 57 58 59 cout << "\nThe pre-order tree traversal of the nodes’ values is: "; preorder(root); cout << "\n" << endl; 60 61 62 63 64 return 0; } 65
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