Get an education: In 2012 the General Social Survey asked 847 adults how many years of education they had. The sample mean was 8.55 years with astandard deviation of 8.52 years.Part: 0 / 2Part 1 of 2(a) Construct a 99.9% confidence interval for the mean number of years of education. Round the answers to at least two decimal places.A 99.9% confidence interval for the mean number of years of education is

Given,sample size(n)=847sample mean(x¯)=8.55sample standard deviation(s)=8.52degrees of…

Answered: Get an education: In 2012 the General…

MATLAB: An Introduction with Applications

6th Edition

ISBN:9781119256830

Author:Amos Gilat

Publisher:Amos Gilat

Chapter1: Starting With Matlab

Section: Chapter Questions

Problem 1P

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Similar questions

Tina catches a 14-pound bass. She does not know the population mean or standard deviation. So she takes a sample of five friends and they say the last bass they caught was 9, 12, 13, 10, and 10 pounds. Find the t and calculate a 95% (α = .05) confidence interval.
You want to find out the average monthly rent for a studio apartment in Los Angeles. Out of a sample of n = 100 you find the sample average rent to be ?̅ = $1275. Assume you know the population standard deviation for studios’ monthly rent to be σ = $180. Develop a 90% confidence interval estimate of the population average monthly rent for studio apartments in Los Angeles
The current speed limit is 60 mph. This sample of speeds was taken at 4pm on a Monday. Use the data to construct a 80% confidence interval estimate of the standard deviation for the population speeds. 60 62 62 65 56 62 54 61 60 61 69 58 66 what is the lower limit what is the upper limit
College tuition: A simple random sample of 35 colleges and universities in the United States has a mean tuition of $17,500 with a standard deviation of $10,800. Construct a 90% confidence interval for the mean tuition for all colleges and universities in the United States. Round the answers to the nearest whole number. A 90% confidence interval for the mean tuition for all colleges and universities is < µ <
find a random sample size of 61 and a sample mean of 14.8 standard deviation 4.2. find 99%confidence interval what does E=? what is the confidence interval
Sample size 42, mean. 53.1, and standard deviation 8.2 An 80% confidence interval for population mean is
Let's go to the movies: A random sample of 42 Foreign Language movies made since the year 2000 had a mean length of 129.2 minutes, with a standard deviation of 13.9 minutes. Part: 0 / 2 0 of 2 Parts Complete Part 1 of 2 (a) Construct a 95% confidence interval for the true mean length of all Foreign Language movies made since 2000 . Round the answers to one decimal place. A 95% confidence interval for the true mean length of all Foreign Language movies made since 2000 is <<μ .
In order to estimate the average amount a customer spends on a meal in a major restaurant, data was collected from a sample of 30 customers. Suppose the population standard deviation is $3 . If the sample mean is $22, what is the 95% confidence interval for the population mean? Select one: a. [20.93 , 23.07] b. [20.59 , 23.41] c. [21.99 , 22.01] d. [20.95 , 23.05]
College tuition: A simple random sample of 40 colleges and universities in the United States has a mean tuition of S18,600 with a standard deviation of S10,800. Construct a 95% confidence interval for the mean tultion for all colleges and universities in the United States. Round the answers to the nearest whole number. A 95% confidence interval for the mean tuition for all colleges and universities is
Researchers studied the mean egg length (in millimeters) for a bird population. After taking a random sample of eggs, they obtained a 95% confidence interval of (45,60). What is the value of the margin of error? Choose the correct answer below. A. 15 mm B. 52.5 mm O c. 7.5 mm O D. 1.96
In a random sample of 38 criminals convicted of a certain crime, it was determined that the mean length of sentencing was 61 months, with a standard deviation of 8 months. Construct and interpret a 95% confidence interval for the mean length of sentencing for this crime. Select the correct choice below and fill in the answer boxes to complete your choice.(Use ascending order. Round to one decimal place as needed.) A. 95% of the sentences for the crime are between ____ and ____ months. B. There is a 95% probability that the mean length of sentencing for the crime is between ____ and ____ months. C. We can be 95% confident that the mean length of sentencing for the crime is between
A random sample of 55 airline pilots had an average yearly income of $99,000 with a standard deviation of $15,000. If we want to determine a 95% confidence interval for the average yearly income, what is the value of t? Develop a 95% confidence interval for the average yearly income of all pilots.

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