The 2002 general Social Survey asked a large number of people how much time they spent watching TV each day. The mean number of hours was 4.16 with a standard deviation of 2.23. Assume that in a sample of 52 teenagers, the sample standard deviation of daily TV time is 1.98 hours, and that the population of TV watching times is normally distributed. Under 10% significance level can you conclude that the population standard deviation of TV watching times for teenagers is different from 2.23? Procedure: One variance x² Hypothesis Test Assumptions: (select everything that applies) O Population standard deviation is known O The number of positive and negative responses are both greater than 10 O Population standard deviation is unknown O Simple random sample O Normal population O Sample size is greater than 30 Step 1. Hypotheses Set-Up: is the where population mean hr Ho: G 2.23 v and the units are Ha: G 223 and the test is (Right-Tailed Step 2. The significance level a Step 3. Compute the value of the test statistic: Select an answer (Round the answer to 3 decimal places) Step 4. Testing Procedure: (Round the answers to 3 decimal places) CVA PVA Provide the critical value(s) for the Rejection Region: Compute the P-value of the test statistic: left CV is and right CV is P-value is Step 5. Decision: CVA PVA Is the test statistic in the rejection region? Is the P-value less than the significance level? Conclusion: Select an answer Step 6. Interpretation: At 10% significance level we Select an answer hypothesis in favor of the alternative hypothesis. ) have sufficient evidence to reject the null