Round the answers to one decimal place.   A  95%  confidence interval for the true mean length of all Foreign Language movies made since  2000  is    <<μ

Q: A researcher wants to estimate the mean blood cholesterol level of young men ages 15-25 with a…

A: Given that,  Confidence interval =83.56% Standard deviation=35 mg/dl We have to find the value of n

Q: Give a 95% confidence interval for the true mean time the team spent preparing for the game.…

A:

Q: The mayor is interested in finding a 90% confidence interval for the mean number of pounds of trash…

A: Given: Sample Size (n)=226 Sample Mean (X)=37.3 Standard deviation (s)=7.2

Q: Last Wednesday, a random sample of 12 students were surveyed to find how long it takes to walk from…

A: Sample mean = x̅ = 10 Sample size = n = 12 Sample S.D = s = 2.5

Q: How large a sample should be selected to provide a 90% confidence interval with a margin of error of…

A: Given,population standard deviation(σ)=60margin of error(E)=9α=1-0.90=0.1α2=0.05Z0.05=1.645

Q: A researcher is interested in finding a 95% confidence interval for the mean number of times per day…

A:

Q: A random sample of 18 positions in a large hospital show that they were on average 43.4 hours per…

A:

Q: Overweight Men For a random sample of 70 overweight men, the mean of the number of pounds that they…

A: Sample size Sample mean Population standard deviation

Q: A particular country contains 4000 mountain peaks. A sample of 36 of the country’s  peaks is…

A: Given,sample size(n)=36sample mean(x¯)=6240degrees of…

Q: For a random sample of 55 overweight men, the mean of the number of pounds that they were overweight…

A: It is given that the sample mean is 32 and the population standard deviation is 4.1.

Q: How large a sample should be selected to provide a 95%  confidence interval with a margin of error…

A:

Q: For a random sample of 55 overweight men, the mean of the number of pounds that they were overweight…

A: Given,sample size(n)=55sample mean(x)=32standard deviation(σ)=4.1α=1-0.90=0.1α2=0.05z0.05 =1.645

Q: A random sample of 5 fields of rye has a mean yield of 21.3 bushels per acre and standard deviation…

A: Given, Sample size, n = 5 Sample mean, x = 21.3 bushels per acres Sample mean, s = 2.53 bushels per…

Q: Among various ethnic groups, the standard deviation of heights is known to be approximately three…

A:

Q: How large a sample should be selected to provide a 95% confidence interval with a margin of error of…

A: Population standard deviation, sigma is 50. The z-critical value for 95% confidence interval is…

Q: A random sample of  36  drivers used on average  740  gallons of gasoline per year. The standard…

A: The sample size is 36, sample mean is 740 and population standard deviation is 33.

Q: Psychologists at a university compared the levels of alcohol consumption of male and female freshman…

A: Fol

Q: A group of 65 randomly selected students have a mean score of 30.6 with a standard deviation of 5.4…

A:

Q: A researcher is interested in finding a 95% confidence interval for the mean number of times per day…

A: Confidence Interval: In statistics, we can say a range of values or set of values of the specified…

Q: How large a sample should be selected to provide a 95% confidence interval with a margin of error of…

A: Givenconfidence interval(c)=95%margin of error(E)=8standard deviation(σ)=10

Q: A random sample of high school students is used to estimate the mean time all high school students…

A: Solution: From the given information, a 99% confidence interval is 1.7 hours to 3.1 hours.

Q: ow large a sample should be selected to provide a 95% confidence interval with a margin of error of…

A: Given Information: Confidence level = 95% = 0.95 Margin of Error = 5 Population standard deviation…

Q: A researcher wants to estimate the mean blood cholesterol level of young men ages 15-25 with a…

A: It is given that the confidence level is 0.8462, the standard deviation is 45, and the margin of…

Q: For a random sample of 70 overweight men, the mean of the number of pounds that they were overweight…

A: Dear Student,  For part 3 confidence level is missing. Kindly repost it with complete data.

Q: In 2002, the mean age of an inmate on death row was 40.7 years with a standard deviation of 9.6…

A: Sample mean =[x] =38.9 Standard deviation =[σ] =9.6 sample size [n] =32 Confidence interval =95%

Q: Student 1 Student 2 Student 3 Student 4 Student 5 Student 6 Student 7 Student 8 Student 9 Height…

A: Given α=0.05nH=9nW=9 Define: X¯H=mean height of the sample of students X¯W=mean weight of the…

Q: researcher is interested in finding a 95% confidence interval for the mean number Minutes students…

A:

Q: A data set includes 108 body temperatures of healthy adult humans having a mean of 98.2°F and a…

A: Solution: Let X be the body temperature of healthy adult human. From the given information,…

Q: One​ year, the mean age of an inmate on death row was 38.1years. A sociologist wondered whether the…

A:

Q: Last Wednesday, a random sample of 16 students were surveyed to find how long it takes to walk from…

A:

Q: A software company is interested in improving customer satisfaction rate from the 55% currently…

A:

Q: For a random sample of  70  overweight men, the mean of the number of pounds that they were…

A: Here, n = 70, CL = 0.99, x=28, and σ=3.8

Q: Provide 90% and 95% confidence intervals for the population mean number of weekly customer contacts…

A: Given n=55 x¯=18.5s=5.2

Q: number

A: Given: Mean, x=3.5 Sample standard deviation, s=1.6 Sample size, n = 219 To compute the confidence…

Q: A sample of twenty newborn elephants had a sample mean of 225 pounds and a sample standard deviation…

A: Here, the population standard deviation is given. Hence, it will be best to use a z- interval.

Q: You draw a simple random sample of 27 items from a Normal Population that has a standard deviation…

A:

Q: Contstruct a 95% confidence interval for the population mean length of time that people have lived…

A: Here, mean is bit larger than the median, so we do not think that this variable has a normal…

Q: At High Fashion shoe store, 23 randomly selected customers spend an average of 33.5 minutes shopping…

A: From the provided information,

Q: clinical trial was conducted to test the effectiveness of a drug used for treating insomnia older…

A: n=26 x¯=98.7Standard deviation =43.9α=1-0.90=0.10