Get an education: In 2012 the General Social Survey asked 833 adults how many years of education they had. The sample meanwas 9.77 years with a standard deviation of 9.53 years.00Part: 0 / 2Part 1 of 2(a) Construct a 99% confidence interval for the mean number of years of education. Round the answers to at least twodecimal places.A 99% confidence interval for the mean number of years of education is<µ<

Given that; Sample size (n) = 833 Sample mean = 9.77 Standard deviation = 9.53 At 99% confidence…

Answered: Get an education: In 2012 the General…

A First Course in Probability (10th Edition)

10th Edition

ISBN:9780134753119

Author:Sheldon Ross

Publisher:Sheldon Ross

Chapter1: Combinatorial Analysis

Section: Chapter Questions

Problem 1.1P: a. How many different 7-place license plates are possible if the first 2 places are for letters and...

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Similar questions

You measure 43 textbooks' weights, and find they have a mean weight of 49 ounces. Assume the population standard deviation is 14.5 ounces. Based on this, construct a 95% confidence interval for the true population mean textbook weight.Give your answers as decimals, to two places _____ < μ < ______
Assume that you want to construct a 95% confidence interval estimate of a population mean. Find an estimate of the sample size needed to obtain the specified margin of error for the 95% confidence interval. The sample standard deviation is given. Margin of error, Eequals=6.1 grams; sample standard deviation, sequals=65.6grams The required sample size is _______? (Round up to the nearest whole number.
In a survey, 16 people were asked how much they spent on their child's last birthday gift. The results were roughly bell-shaped with a mean of $36 and standard deviation of $16. Construct a confidence interval at a 90% confidence level.Give your answers to one decimal place._____ ± _____
Ages of students: A simple random sample of 110 U.S. college students had a mean age of 23.05 years. Assume the population standard deviation is o =4.81 years. Construct a 90% confidence interval for the mean age of U.S. college students. Round the answers to two decimal places. A 90% confidence interval for the mean age of U.S. college students is 22.46 T< u <23.64
Tina catches a 14-pound bass. She does not know the population mean or standard deviation. So she takes a sample of five friends and they say the last bass they caught was 9, 12, 13, 10, and 10 pounds. Find the t and calculate a 95% (α = .05) confidence interval.
You want to find out the average monthly rent for a studio apartment in Los Angeles. Out of a sample of n = 100 you find the sample average rent to be ?̅ = $1275. Assume you know the population standard deviation for studios’ monthly rent to be σ = $180. Develop a 90% confidence interval estimate of the population average monthly rent for studio apartments in Los Angeles
find a random sample size of 61 and a sample mean of 14.8 standard deviation 4.2. find 99%confidence interval what does E=? what is the confidence interval
The distribution of study times for first year students follows a Normal distribution with standard deviation σσ = 54 minutes. Suppose a sample of 487 students found that the mean study time for these students was x¯x¯= 173 minutes per week. Use this to find a 88.28% confidence interval to estimate the mean study time for all students. We are 88.28% confident that the mean study time for first year students is between minutes_____ and ____ minutes. What is the margin of error for your confidence interval?
In a survey, 21 people were asked how much they spent on their child's last birthday gift. The results were roughly bell-shaped with a mean of $30 and standard deviation of $14. Construct a confidence interval at a 80% confidence level.Give your answers to one decimal place. ______ ± _______
Researchers studied the mean egg length (in millimeters) for a bird population. After taking a random sample of eggs, they obtained a 95% confidence interval of (45,60). What is the value of the margin of error? Choose the correct answer below. A. 15 mm B. 52.5 mm O c. 7.5 mm O D. 1.96
Question: Part B. Construct a 95% confidence interval of the mean pulse rate for adult males. __bpm <u<__bpm Multiple Choice: Compare the results. A. The confidence intervals do not overlap, so it appears that adult females have a significantly higher mean pulse rate than adult males. B. The confidence intervals overlap, so it appears that adult males have a significantly higher mean pulse rate than adult females. C. The confidence intervals do not overlap, so it appears that there is no significant difference in mean pulse rates between adult females and adult males. D. The confidence intervals overlap, so it appears that there is no significant difference in mean pulse rates between adult females and adult males.
In a survey, 28 people were asked how much they spent on their child's last birthday gift. The results were roughly bell-shaped with a mean of $44 and standard deviation of $6. Construct a confidence interval at a 98% confidence level.Give your answers to one decimal place._______________ ± _______________Interpret your confidence interval in the context of this problem.

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