Social Networking Sites A recentsurvey of 6 social networkingsites has a mean of 8.9 millionvisitors for a specific month. Thestandard deviation was 3.6million. Find the 90% confidenceinterval of the true mean.Assume the variable is normallydistributed. Round your answersto at least two decimal places.

Answered: Image /qna-images/answer/137ff9c9-91e1-40e1-b38f-3c52646ed3be.jpg

Answered: Social Networking Sites A recent survey…

MATLAB: An Introduction with Applications

6th Edition

ISBN:9781119256830

Author:Amos Gilat

Publisher:Amos Gilat

Chapter1: Starting With Matlab

Section: Chapter Questions

Problem 1P

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A student graduated from a 4 -year college with an outstanding loan of $9563 where the average debt is $8558 with a standard deviation of $1860 . Another student graduated from a university with an outstanding loan of $12,370 where the average of the outstanding loans was $10,318 with a standard deviation of $2144 Find the corresponding z score for each student. Round z scores to two decimal places. College student: =z University student: =z
Randy took a standardized test that is normally distributed. He scored a 105 on the test. The nationwide mean score on the test was 94 and the standard deviation was 6.2. What percent of the tested population scored higher than Randy on the test? Round to the nearest whole percent. O 2% 4% 96% O 94% 11%
Test scores for a history class had a mean of 69 with a standard deviation of 4.5. Test scores for a physics class had a mean of 79 with a standard deviation of 3.5. Suppose a student gets a 75 on the history test and 83 on the physics test. Calculate the z- score for each test. On which test did the student perform better? A. B. C. D. History exam; history z-score is 1.33; physics z-score is 1.14 Physics exam; history z-score is 1.33; physics z-score is 1.14 History exam; history z-score is -1.33; physics z-score is -1.14 Physics exam; history z-score is -1.33; physics z-score is -1.14
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Students in the psychology department at General State University consumes an average of 7 sodas per day with a standard deviation of 2.5. the distribution is normal. Explain how you would go about answering the following questions (include your answer to the question in your response): How many sodas would an individual at the 75thpercentile drink per day?
Help me please
The systolic blood pressure of adults in the USA is nearly normally distributed with a mean of 118 and standard deviation of 24 .Someone qualifies as having Stage 2 high blood pressure if their systolic blood pressure is 160 or higher.a. Around what percentage of adults in the USA have stage 2 high blood pressure? Give your answer rounded to two decimal places. ________%b. If you sampled 2000 people, how many would you expect to have BP> 160? Give your answer to the nearest person.________ peoplec. Stage 1 high BP is specified as systolic BP between 140 and 160. What percentage of adults in the US qualify for stage 1?________ %d. Your doctor tells you you are in the 30th percentile for blood pressure among US adults. What is your systolic BP? Round to 2 decimal places._______ lbs
Many college admissions want to know your class percentage in addition to your grades. The grades are normally distributed. A certain university insists that a student place in at the 90th percentile. if the mean is 79.45 and the standard deviation is 5.37, what is the 90th percentile? a.88.07 b.85.01 c.86.33 d.90
Solve the problem. Round to the nearest tenth. min one region, the September energy consumption levels for single family homes are found to be normally distributed with a mean of 1050 kWh and a standard deviation of 218 kWh. Find which is the consumption level separating the bottom 45% from the top 55%.
The annual rainfall in a town has a mean of 54.57 inches and a standard deviation of 12.84 inches. Last year there was rainfall of 71 inches. How many standard deviations away from the mean is that? Round your answer to two decimal places.
The state and will spend 15 hours average a week and class and the standard deviation is 2 hours what percentage of students spend less than 12 hours in class
The heights of women follow a normal distribution with a mean height of 63.7, and a standard deviation in height of 2.9 in. What height separates the shortest 5% of women from the rest. Round your result to 1 decimal place. 68.5 inches 65.4 inches None of these 58.9 inches -1.6 inches

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