A company produces steel rods. The lengths of the steel rods are normally distributed with a mean of 154.5 cm and a standard deviation of 2.3 cm.Find \( P_{45} \), which is the length separating the shortest 45% of rods from the longest 55%.\[ P_{45} = \] _____ cm\[ (z = \] _____ \() \)Shade: Left of a value.Click and drag the arrows to adjust the values.---**Graph Description:**The graph is a standard normal distribution curve (bell curve) with the x-axis marked from -4 to 4. There is a shaded blue area on the left side of the curve, which represents the shortest 45% of the distribution. An arrow pointing to a position of -1.5 on the x-axis indicates the z-score for this percentile. The curve is symmetrical, showing the probabilities of different lengths within the normal distribution.

The Z-score of a random variable X is defined as follows: Z = (X – µ)/σ. Here, µ and σ are the mean…

company produces steel rods. The lengths of the steel rods are normally distributed with a mean of 154.5 cm and a standard deviation of 2.3 cm. A Find P45 which is the length separating the shortest 45% rods from the longest 55%. P45 %3D cm (z = %3D Shade: Left of a value Click and drag the arrows to adjust the values. -4 -3 -2 1 -1 3. 4 -1.5

company produces steel rods. The lengths of the steel rods are normally distributed with a mean of 154.5 cm and a standard deviation of 2.3 cm. A Find P45 which is the length separating the shortest 45% rods from the longest 55%. P45 %3D cm (z = %3D Shade: Left of a value Click and drag the arrows to adjust the values. -4 -3 -2 1 -1 3. 4 -1.5

MATLAB: An Introduction with Applications

6th Edition

ISBN:9781119256830

Author:Amos Gilat

Publisher:Amos Gilat

Chapter1: Starting With Matlab

Section: Chapter Questions

Problem 1P

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