A nutritionist wants to determine how much time nationally people spend eating and drinking. Suppose for a random sample of 936 people age 15 or older, the mean amount of time spent eating or drinking per day is 1.79 hours with a standard deviation of 0.58 hour Complete parts (a) through (d) below. II OD. The sample size is less than 10% of the population. (c) Determine and interpret a 90% confidence interval for the mean amount of time Americans age 15 or older spend eating and drinking each day. Select the correct choice below and fill in the answer boxes, if applicable, in your choice. (Type integers or decimals rounded to three decimal places as needed. Use ascending order) OA. There is a 90% probability that the mean amount of time spent eating or drinking per day is between and hours. B. The nutritionist is 90% confident that the mean amount of time spent eating or drinking per day is between 1.759 and 1.821 hours. OC. The nutritionist is 90% confident that the amount of time spent eating or drinking per day for any individual is between OD. The requirements for constructing a confidence interval are not satisfied. (d) Could the interval be used to estimate the mean amount of time a 9-year-old spends eating and drinking each day? Explain. 4 and hours. OA. Yes, the interval is about individual time spent eating or drinking per day and can be used to find the mean amount of time a 9-year-old spends eating and drinking each day OB. Yes, the interval is about the mean amount of time spent eating or drinking per day for people people age 15 or older and can be used to find the mean amount of time spent eating or drinking per day for 9-year-olds. OC. No, the interval is about people age 15 or older. The mean amount of time spent eating or drinking per day for 9-year-olds may differ OD. No, the interval is about individual time spent eating or drinking per day and cannot be used to find the mean time spent eating or drinking per day for specific age. OE. A confidence interval could not be constructed in part (c).

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A nutritionist wants to determine how much time nationally people spend eating and drinking. Suppose for a random sample of 936 people age 15 or older, the mean amount of time spent eating or
drinking per day is 1.79 hours with a standard deviation of 0.58 hour. Complete parts (a) through (d) below.
OD. The sample size is less than 10% of the population
(c) Determine and interpret a 90% confidence interval for the mean amount of time Americans age 15 or older spend eating and drinking each day.
Select the correct choice below and fill in the answer boxes, if applicable, in your choice.
(Type integers or decimals rounded to three decimal places as needed. Use ascending order.)
OA. There is a 90% probability that the mean amount of time spent eating or drinking per day is between
and hours.
B. The nutritionist is 90% confident that the mean amount of time spent eating or drinking per day is between 1.759 and 1:821 hours.
OC. The nutritionist is 90% confident that the amount of time spent eating or drinking per day for any individual is between
OD. The requirements for constructing a confidence interval are not satisfied.
and
hours.
(d) Could the interval be used to estimate the mean amount of time a 9-year-old spends eating and drinking each day? Explain.
hs
OA. Yes, the interval is about individual time spent eating or drinking per day and can be used to find the mean amount of time a 9-year-old spends eating and drinking each day
OB. Yes, the interval is about the mean amount of time spent eating or drinking per day for people people age or ol and can be used to find the mean amount of time spent eating or drinking
per day for 9-year-olds.
OC. No, the interval is about people age 15 or older. The mean amount of time spent eating or drinking per day for 9-year-olds may differ.
OD. No, the interval is about individual time spent eating or drinking per day and cannot be used to find the mean time spent eating or drinking per day for specific age.
OE. A confidence interval could not be constructed in part (c).
Transcribed Image Text:A nutritionist wants to determine how much time nationally people spend eating and drinking. Suppose for a random sample of 936 people age 15 or older, the mean amount of time spent eating or drinking per day is 1.79 hours with a standard deviation of 0.58 hour. Complete parts (a) through (d) below. OD. The sample size is less than 10% of the population (c) Determine and interpret a 90% confidence interval for the mean amount of time Americans age 15 or older spend eating and drinking each day. Select the correct choice below and fill in the answer boxes, if applicable, in your choice. (Type integers or decimals rounded to three decimal places as needed. Use ascending order.) OA. There is a 90% probability that the mean amount of time spent eating or drinking per day is between and hours. B. The nutritionist is 90% confident that the mean amount of time spent eating or drinking per day is between 1.759 and 1:821 hours. OC. The nutritionist is 90% confident that the amount of time spent eating or drinking per day for any individual is between OD. The requirements for constructing a confidence interval are not satisfied. and hours. (d) Could the interval be used to estimate the mean amount of time a 9-year-old spends eating and drinking each day? Explain. hs OA. Yes, the interval is about individual time spent eating or drinking per day and can be used to find the mean amount of time a 9-year-old spends eating and drinking each day OB. Yes, the interval is about the mean amount of time spent eating or drinking per day for people people age or ol and can be used to find the mean amount of time spent eating or drinking per day for 9-year-olds. OC. No, the interval is about people age 15 or older. The mean amount of time spent eating or drinking per day for 9-year-olds may differ. OD. No, the interval is about individual time spent eating or drinking per day and cannot be used to find the mean time spent eating or drinking per day for specific age. OE. A confidence interval could not be constructed in part (c).
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