g, is isolated and it fails to complement c.

Below is a partially filled in complementation table. Please answer the following questions. 1 2 3 4 LO 5 6 1 2 I 3 4 5 4 + + 5 6 a. If you were to perform a complementation test with mutants 1 and 2, what would be the result? [Select] b. If you were to perform a complementation test with mutants 5 and 6, what would be the result? [Select] c. If you were to perform a complementation test with mutants 3 and 4, what would be the result? [Select] d. There is one complementation group that you can determine from the information above. If you performed a complementation test with mutant 1 and 6 and there was growth, would you say that the mutants were part of that complementation group? [Select] e. What is the minimum number of complementation groups that could exist based on the information above? [Select] f. What is the maximum number of complementation groups that could exist based on the information above? [Select]

During the analysis of seven rII mutations in phage T4, mutants1, 2, and 6 were in cistron A, while mutants 3, 4, and 5 were incistron B. Of these, mutant 4 was a deletion overlapping mutant5. The remainder were point mutations. Nothing was knownabout mutant 7. Predict the results of complementation (+ or -)between 1 and 2; 1 and 3; 2 and 4; and 4 and 5.

Now, figure out the complementation groups. This shows how many genes are involved in this pathway. Some of the mutant classes in the previous problem must contain more than one complementation group (gene) For example class 2 is defined by mutants 1,3,4,6, and 7. These mutants may, or may not, all be in the same gene. Complementation testing will help you know if they are, or are not, in the same gene. So there are actually additional steps between some of the letters. For example, maybe instead of XàY, it is really XàFàGàY.

In the genotype presented (genomic plus plasmid genes), which of the following statements Is phenotype? genome: IS P O`z+Y° plasmid: I* Pt otzY+ no production of either B-gal and permease O B-gal and permease induced when lactose is present no B-gal is produced and expression of permease when lactose is present constitutive expression of B-gal and permease constitutive expression of B-gal and no expression of permease

b d f a + + + + d + e The normal flower color in garden peas is purple. A researcher interested in the biochemical pathway leading to purple flower color has isolated six white mutants, each of which is recessive to purple. The six white mutants have been designated a, b, c, d, e and f. Complementation tests have been carried out for each pair of mutants, and the results are indicated in the table above, where a “+" indicates complementation (purple flower color in the offspring of the complementation test) and a “-" indicates no complementation (white flower color). What is the number of genes (complementation groups) identified by these mutants? +| +|+|+|+

Biology = genetics  please do Challenge problem 3  Now, figure out the complementation groups. This shows how many genes are involved in this pathway. Some of the mutant classes in the previous problem must contain more than one complementation group (gene) For example class 2 is defined by mutants 1,3,4,6, and 7. These mutants may, or may not, all be in the same gene. Complementation testing will help you know if they are, or are not, in the same gene. So there are actually additional steps between some of the letters. For example, maybe instead of XàY, it is really X->F->G->Y.

For each genotype in the table below, determine whether or not functional B-gal will be produced in the presence or absence of the inducer. Write a plus (+) if B-gal is produced or a minus (-) if it is not. ma Chromosome F' lac (plasmid) - Inducer + Inducer ---- --- --- I*O*Z I*O°Z+ I*O*Z* I* = wildtype repressor |- - no functional repressor produced O* - wildtype operator OC = operator mutation prevents repressor from binding %3D

Determine the coefficient of coincidence and the interference

Can you explain a brief description of each of the methods used?