Freshwater60 cm10 cm40 cm70 cmMercury-AirSeawater,2 Fresh and seawater flowing in parallel horizontal pipelinesare connected to each other by a double U-tube manometer.Determine the pressure difference between the twopipelines (P₁-P2). Take the density of seawater at thatlocation to be psea = 1035 kg/m³. The specific gravities ofmercury, water and air are 13.6, 1.0 and 0.0013, respectively.

Given Data:The density of air is:(ρair=1.2kg/m3)The density of sea water is:(ρsea=1035,kg/m3)The…

Answered: Fresh water 60 cm 10 cm 40 cm 70 cm…

Elements Of Electromagnetics

7th Edition

ISBN:9780190698614

Author:Sadiku, Matthew N. O.

Publisher:Sadiku, Matthew N. O.

ChapterMA: Math Assessment

Section: Chapter Questions

Problem 1.1MA

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Two pipes A & B carries an oil of specific gravities 0.9 & 1.2 respectively. A U tubedifferential manometer is connected between the pipes. The center of the pipe A is 1 mabove the pipe B. The height of oil in right limb is 30 cm. Also, the mercury leveldifference is found in right limb as 10 cm. Find the pressure difference between these twopipes in kPa. Sketch the arrangement neatly.
The pressure difference between an oil pipe and water pipe is measured by a double-fluid manometer, as shown in the figure. For the given fluid heights and specific gravities, calculate the pressure difference AP= PB - PA. The specific gravities are 13.5 for mercury, 1.26 for glycerin, and 0.88 for oil. Take the standard density of water to be pw=1000 kg/m³. The heighth of mercury in the manometer is 25 cm. Water SG=1.0 Mercury SG= 13.5 55 cm The pressure difference is Glycerin SG=1,26 10 cm 12 cm Oil SG=0.88 kPa.
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A manometer consists of two tubes A and B, with verticalaxes and uniform cross-sectional areas 500 mm2and 800 mm2respectively, connected by a U-tube C of cross-sectional area70 mm2throughout. Tube A contains a liquid of relative density0.8; tube B contains one of relative density 0.9. The surfaceof separation between the two liquids is in the vertical side of Cconnected to tube A. What additional pressure, applied to thetube B, would cause the surface of separation to rise 60 mm inthe tube C?
The right limb of a simple U-tube manometer containing mercury is open to the atmosphere while the left limb is connected to a pipe in which a fluid of SG = 0.9 is flowing. The center of the pipe is 12 cm below the level of mercury in the right limb. Find the pressure of fluid in the pipe if the difference of mercury level in the two limbs is 20 cm. Use SGHg = 13.6. P A 12 I 21K 20 cm
A U-tube containing mercury (sg = 13.6) has itsright-hand limb open to the atmosphere and the left-handlimb connected to a pipe conveying water under pressure,the difference in the level of mercury in the two limbs being200 mm. If the mercury level in the left-hand limb is 400 mmbelow the pipe's center line, find the pipeline's absolutepressure (kPa). Also, find the new difference in levels ofmercury in the U-tube if the pressure in the pipe falls by 2kPa.
A multifluid container is connected to a U-tube, as shown in the figure. For the given specific gravitles and fluid column heights. determine the gage pressure at A. Also determine the height of a mercury column that would create the same pressure at A. The column heighth of oil is 86 cm. The specific gravitles are 1.26 for glycerin and 0.90 for oll. We take the standard density of water to be Pw=1000 kg/m³ and the specific gravity of mercury to be 13.6. h 35 cm 18 cm Į Oil SG-0.90 Water Glycerin SG-1.26 90 cm 15 cm The gage pressure at A is kPa. The height of a mercury column that would create the same pressure at A is cm.
(1) A simple, vertical U-tube manometer is used to measure the differencebetween two gas pressures.Write down an equation for the pressure difference in terms of the difference inthe level of the fluid in the manometer. Describe briefly, with the help ofdiagrams, two modifications to the basic design which offer greater sensitivity tosmall pressure differences. Give equations for their use. ii) An extractor fan draws air from a room and delivers it to the surroundingsthrough a 5m long circular duct of diameter 0.1m. The friction coefficientfor the duct flow is 0.002. The fan characteristic, relating its total pressurerise, ∆P (Nm-2) to the volume flow rate is: ∆P = 103−7x104Q 2. What is therate of flow through the duct?You may assume that the room and surroundings are both at atmosphericpressure; state and justify any other assumptions you make.
A single U – tube manometer containing mercury is connected to a pipe in which a fluid of sp. gr. 0.8 and having a vacuum pressure is flowing. The other end of the manometer is open to atmosphere. Find the vacuum pressure in pipe, if the difference of mercury level in the two limbs is 40cm and the height of fluid in the left from the center of pipe is 15 cm below.
The pressure difference between an oil pipe and water pipe is measured by a double-fluid manometer, as shown in the figure below. For the given fluid heights and specific gravities, calculate the pressure difference ΔP = PB - PA. Take: The density of water: ρw=1000 kg/m3 and the gravitational acceleration: g = 9.81 m/s2.
As shown in the figure, an inclined manometer is used to measure the pressure of the gas within the reservoir. The manometer fluid is mercury, which has a density of 845 Ib/ft3. The manometer fluid rises a distance d = 12 inches along the manometer tube, which is inclined e = 20° from the horizontal. The atmospheric pressure is 14.7 Ibf/in? and the acceleration of gravity is 32.2 ft/s?. Patm = 14.7 Ibf/in.? Gas reservoir g = 32.2 ft/s? a 20 in. Mercury (p = 845 Ib/ft³) Determine the gas pressure, in Ibf/in?. Express the pressure as a gage or a vacuum pressure, as appropriate, in Ibf/in2.

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