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(25 pts) The 50-lb block rests on the smooth surface. A force F = (40+s²) lb, which s is in ft, acts on the block in the direction shown. If the spring is originally unstretched (s = 0) and the block is at rest, determine the power developed by the force the instant the block has moved s = 1.5 ft. F. 30° k = 20 lb/ft wwwwww

(25 pts) The 50-lb block rests on the smooth surface. A force F = (40+s²) lb, which s is in ft, acts on the block in the direction shown. If the spring is originally unstretched (s = 0) and the block is at rest, determine the power developed by the force the instant the block has moved s = 1.5 ft. F. 30° k = 20 lb/ft wwwwww

Elements Of Electromagnetics
Elements Of Electromagnetics
7th Edition
ISBN:9780190698614
Author:Sadiku, Matthew N. O.
Publisher:Sadiku, Matthew N. O.
ChapterMA: Math Assessment
Section: Chapter Questions
Problem 1.1MA
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(25 pts) The 50-lb block rests on the smooth surface. A force F = (40+s²) lb, which s is in ft, acts on the block in the direction shown. If the spring is originally unstretched (s = 0) and the block is at rest, determine the power developed by the force the instant the block has moved s = 1.5 ft. F. 30° k = 20 lb/ft wwwwww
Transcribed Image Text:(25 pts) The 50-lb block rests on the smooth surface. A force F = (40+s²) lb, which s is in ft, acts on the block in the direction shown. If the spring is originally unstretched (s = 0) and the block is at rest, determine the power developed by the force the instant the block has moved s = 1.5 ft. F. 30° k = 20 lb/ft wwwwww
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