1 m G E F 3 m B A D 3 m A 2m → Prob. 17-56 C HW-Problem (HWS) w=200x481 -1962 N F-1.5N-1500 N Find: F at the BE exerts a vertical force FBD when 90° 1500 N 3m instant-90 The platform is at rest when +45 M=200 kg of crate (ap) Ja col 2Fman F-F200 [3] where, t means tangental acceleration Fas-F 200[30.035"] F-F-7(5), in means normal acceleration. Cab -αr-sa (ashwr 3w" Please explain Vising-Fsine - 200(8x) 1462sino-soosing 600 Finding angular velocity 1500 (233-2-0 So. Why are these 2PA+ FED 3000 (2) So FAB-1217,39 N -Sade 8 88 aine de negative solving (3)+(2): Feb 564 42 N where did this come = 0.77 [ce] 037 VIS-] from this concept Please explain Why work is positive + force is negative Please give me clear + Concephal explanation! At 0.90°; 1.0435 /
1 m G E F 3 m B A D 3 m A 2m → Prob. 17-56 C HW-Problem (HWS) w=200x481 -1962 N F-1.5N-1500 N Find: F at the BE exerts a vertical force FBD when 90° 1500 N 3m instant-90 The platform is at rest when +45 M=200 kg of crate (ap) Ja col 2Fman F-F200 [3] where, t means tangental acceleration Fas-F 200[30.035"] F-F-7(5), in means normal acceleration. Cab -αr-sa (ashwr 3w" Please explain Vising-Fsine - 200(8x) 1462sino-soosing 600 Finding angular velocity 1500 (233-2-0 So. Why are these 2PA+ FED 3000 (2) So FAB-1217,39 N -Sade 8 88 aine de negative solving (3)+(2): Feb 564 42 N where did this come = 0.77 [ce] 037 VIS-] from this concept Please explain Why work is positive + force is negative Please give me clear + Concephal explanation! At 0.90°; 1.0435 /
Elements Of Electromagnetics
7th Edition
ISBN:9780190698614
Author:Sadiku, Matthew N. O.
Publisher:Sadiku, Matthew N. O.
ChapterMA: Math Assessment
Section: Chapter Questions
Problem 1.1MA
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Question
I have already done the question, but have some questions on the steps, please just answer that. The solution is already provided. Please answer with depth and clarity.
A 200-kg crate is placed on a platform and moved vertically through a hydraulic
cylinder BE that exerts a vertical force of F=1.5 kN. Determine the force developed in links AB
and CD at the instant θ=90°. The platform is at rest when θ=45°. Neglect the mass of the links
and the platform.
Transcribed Image Text:1 m
G
E
F
3 m
B
A
D
3 m
A
2m →
Prob. 17-56
C
![HW-Problem (HWS)
w=200x481
-1962 N
F-1.5N-1500 N
Find: F at the
BE exerts a vertical force
FBD when 90°
1500 N
3m
instant-90
The platform is at rest
when +45
M=200 kg of crate
(ap)
Ja
col
2Fman
F-F200 [3]
where, t means tangental acceleration
Fas-F 200[30.035"]
F-F-7(5),
in means normal acceleration.
Cab -αr-sa
(ashwr 3w"
Please explain
Vising-Fsine - 200(8x)
1462sino-soosing 600
Finding angular velocity
1500 (233-2-0 So.
Why are
these
2PA+ FED 3000 (2)
So
FAB-1217,39 N
-Sade
8 88
aine de
negative solving (3)+(2):
Feb 564 42 N
where
did this
come
= 0.77 [ce]
037
VIS-]
from
this concept
Please explain
Why work is positive
+ force is negative
Please give
me clear +
Concephal
explanation!
At 0.90°; 1.0435 /](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2Fe933bc49-41c0-49a8-92f9-d1ccbbfebc81%2Fa8be18ef-b635-4180-896f-34f98646c82a%2Fh5vfkap_processed.jpeg&w=3840&q=75)
Transcribed Image Text:HW-Problem (HWS)
w=200x481
-1962 N
F-1.5N-1500 N
Find: F at the
BE exerts a vertical force
FBD when 90°
1500 N
3m
instant-90
The platform is at rest
when +45
M=200 kg of crate
(ap)
Ja
col
2Fman
F-F200 [3]
where, t means tangental acceleration
Fas-F 200[30.035"]
F-F-7(5),
in means normal acceleration.
Cab -αr-sa
(ashwr 3w"
Please explain
Vising-Fsine - 200(8x)
1462sino-soosing 600
Finding angular velocity
1500 (233-2-0 So.
Why are
these
2PA+ FED 3000 (2)
So
FAB-1217,39 N
-Sade
8 88
aine de
negative solving (3)+(2):
Feb 564 42 N
where
did this
come
= 0.77 [ce]
037
VIS-]
from
this concept
Please explain
Why work is positive
+ force is negative
Please give
me clear +
Concephal
explanation!
At 0.90°; 1.0435 /
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