b) Solution a) y Input link R 02 K₁ = 3 K2=0.67 K3 = 2 A = -0.7113 B = -1 C=3.556 Intermediate link Fixed link R₁ Output link R₁ K4=0.857 K5 = -0.2857 D= -1.6774 E = -1 F = 2.59 c) The output angle = 041 477.3° 041 = 477.3-360 = 117.3° (open) 041216.4° (crossed) The intermediate angle • 031 448.8° 031 = 448.8360 = 88.8° (open) • 032 = 244.8° (crossed) 04
b) Solution a) y Input link R 02 K₁ = 3 K2=0.67 K3 = 2 A = -0.7113 B = -1 C=3.556 Intermediate link Fixed link R₁ Output link R₁ K4=0.857 K5 = -0.2857 D= -1.6774 E = -1 F = 2.59 c) The output angle = 041 477.3° 041 = 477.3-360 = 117.3° (open) 041216.4° (crossed) The intermediate angle • 031 448.8° 031 = 448.8360 = 88.8° (open) • 032 = 244.8° (crossed) 04
Elements Of Electromagnetics
7th Edition
ISBN:9780190698614
Author:Sadiku, Matthew N. O.
Publisher:Sadiku, Matthew N. O.
ChapterMA: Math Assessment
Section: Chapter Questions
Problem 1.1MA
Related questions
Question
What do crossed and open mean? Please explain exactly on this drawing only and when it is crossed and open?
and When do we decrease 360 and when do we increase 360? with all explination on the graph only i will give u good feedback please

Transcribed Image Text:b)
Solution
a)
y
Input link R
02
K₁ = 3
K2=0.67
K3 = 2
A = -0.7113
B = -1
C=3.556
Intermediate
link
Fixed link
R₁
Output link
R₁
K4=0.857
K5 = -0.2857
D= -1.6774
E = -1
F = 2.59
c) The output angle
=
041 477.3° 041 = 477.3-360 = 117.3° (open)
041216.4° (crossed)
The intermediate angle
• 031 448.8° 031 = 448.8360 = 88.8° (open)
• 032 = 244.8° (crossed)
04
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