Free body diagram Draw the free body diagram (FBD) for this system. To draw the free body dagram, we assume that the bar is displaced a small amount in the positive direction of e. Important For the free body diagram, the forces also need to be labelledt You can draw the forces by cicking the application point (etters) and dragging or using the drop dovn with the draw button. If you drew them by clicking and dragging, dlick the force vector to label it from the dropdown menu above. Ithe label on the force doesnt appear on the diagram, you havent quite done itright and the question will keep getting graded as incomect even if you have the comect amows 600000 kz Equation of Motion Since the bar undergoes rotational motion, Nevtor's second law is written by writing a sum of moments around the pivot point (sum of moments cause rotational motion). Positive moments are those that are in the direction that tend to move things in what is defined as the positive direction for e. In other words, a positive moment wants to send eins positive direction (here clockwise) and a negative moment will send e in its negative direction The equation of motion wll look ike Here, Jo is the moment of inerta of the bar about the phvot point, O. and the Ma are the moments due to the two springs and gravity The moment of inertia of the bar about the pivot point O is given by Section Attempt 1 ofS Verity
Free body diagram Draw the free body diagram (FBD) for this system. To draw the free body dagram, we assume that the bar is displaced a small amount in the positive direction of e. Important For the free body diagram, the forces also need to be labelledt You can draw the forces by cicking the application point (etters) and dragging or using the drop dovn with the draw button. If you drew them by clicking and dragging, dlick the force vector to label it from the dropdown menu above. Ithe label on the force doesnt appear on the diagram, you havent quite done itright and the question will keep getting graded as incomect even if you have the comect amows 600000 kz Equation of Motion Since the bar undergoes rotational motion, Nevtor's second law is written by writing a sum of moments around the pivot point (sum of moments cause rotational motion). Positive moments are those that are in the direction that tend to move things in what is defined as the positive direction for e. In other words, a positive moment wants to send eins positive direction (here clockwise) and a negative moment will send e in its negative direction The equation of motion wll look ike Here, Jo is the moment of inerta of the bar about the phvot point, O. and the Ma are the moments due to the two springs and gravity The moment of inertia of the bar about the pivot point O is given by Section Attempt 1 ofS Verity
Elements Of Electromagnetics
7th Edition
ISBN:9780190698614
Author:Sadiku, Matthew N. O.
Publisher:Sadiku, Matthew N. O.
ChapterMA: Math Assessment
Section: Chapter Questions
Problem 1.1MA
Related questions
Question
![Free body diagram
Draw the free body diagram (FBD) for this system. To draw the free body diagram, we assume that the bar is displaced a small amount in the positive
direction of 0. Important: For the free body diagram, the forces also need to be labelled! You can draw the forces by clicking the application point
(letters) and dragging or using the drop down with the 'draw' button. If you drew them by clicking and dragging, click the force vector to label it from the
dropdown menu above. If the label on the force doesn't appear on the diagram, you haven't quite done it right and the question will keep getting graded as
incorrect even if you have the correct arrows.
Fs
k2
Fry
Fg
k1
Frx
Equation of Motion
Since the bar undergoes rotational motion, Newton's second law is written by writing a sum of moments around the pivot point (sum of moments cause
rotational motion). Positive moments are those that are in the direction that tend to move things in what is defined as the positive direction for 0. In other
words, a positive moment wants to send e in its positive direction (here clockwise) and a negative moment will send 0 in its negative direction.
The equation of motion will look like
Jo
0 (t)
= Mo1+ Mo2 + Mo3
Here, Jo is the moment of inertia of the bar about the pivot point, O. and the Maj are the moments due to the two springs and gravity.
The moment of inertia of the bar about the pivot point O is given by
Jo
Section Attempt 1 of 5
Verify](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F9c032157-7c51-4ae0-bf11-737222ac0370%2F77a2cf7a-a702-40d4-9dfc-e9ea85b244b0%2Fr8rk5ql_processed.png&w=3840&q=75)
Transcribed Image Text:Free body diagram
Draw the free body diagram (FBD) for this system. To draw the free body diagram, we assume that the bar is displaced a small amount in the positive
direction of 0. Important: For the free body diagram, the forces also need to be labelled! You can draw the forces by clicking the application point
(letters) and dragging or using the drop down with the 'draw' button. If you drew them by clicking and dragging, click the force vector to label it from the
dropdown menu above. If the label on the force doesn't appear on the diagram, you haven't quite done it right and the question will keep getting graded as
incorrect even if you have the correct arrows.
Fs
k2
Fry
Fg
k1
Frx
Equation of Motion
Since the bar undergoes rotational motion, Newton's second law is written by writing a sum of moments around the pivot point (sum of moments cause
rotational motion). Positive moments are those that are in the direction that tend to move things in what is defined as the positive direction for 0. In other
words, a positive moment wants to send e in its positive direction (here clockwise) and a negative moment will send 0 in its negative direction.
The equation of motion will look like
Jo
0 (t)
= Mo1+ Mo2 + Mo3
Here, Jo is the moment of inertia of the bar about the pivot point, O. and the Maj are the moments due to the two springs and gravity.
The moment of inertia of the bar about the pivot point O is given by
Jo
Section Attempt 1 of 5
Verify
Expert Solution
![](/static/compass_v2/shared-icons/check-mark.png)
This question has been solved!
Explore an expertly crafted, step-by-step solution for a thorough understanding of key concepts.
Step by step
Solved in 2 steps
![Blurred answer](/static/compass_v2/solution-images/blurred-answer.jpg)
Knowledge Booster
Learn more about
Need a deep-dive on the concept behind this application? Look no further. Learn more about this topic, mechanical-engineering and related others by exploring similar questions and additional content below.Recommended textbooks for you
![Elements Of Electromagnetics](https://www.bartleby.com/isbn_cover_images/9780190698614/9780190698614_smallCoverImage.gif)
Elements Of Electromagnetics
Mechanical Engineering
ISBN:
9780190698614
Author:
Sadiku, Matthew N. O.
Publisher:
Oxford University Press
![Mechanics of Materials (10th Edition)](https://www.bartleby.com/isbn_cover_images/9780134319650/9780134319650_smallCoverImage.gif)
Mechanics of Materials (10th Edition)
Mechanical Engineering
ISBN:
9780134319650
Author:
Russell C. Hibbeler
Publisher:
PEARSON
![Thermodynamics: An Engineering Approach](https://www.bartleby.com/isbn_cover_images/9781259822674/9781259822674_smallCoverImage.gif)
Thermodynamics: An Engineering Approach
Mechanical Engineering
ISBN:
9781259822674
Author:
Yunus A. Cengel Dr., Michael A. Boles
Publisher:
McGraw-Hill Education
![Elements Of Electromagnetics](https://www.bartleby.com/isbn_cover_images/9780190698614/9780190698614_smallCoverImage.gif)
Elements Of Electromagnetics
Mechanical Engineering
ISBN:
9780190698614
Author:
Sadiku, Matthew N. O.
Publisher:
Oxford University Press
![Mechanics of Materials (10th Edition)](https://www.bartleby.com/isbn_cover_images/9780134319650/9780134319650_smallCoverImage.gif)
Mechanics of Materials (10th Edition)
Mechanical Engineering
ISBN:
9780134319650
Author:
Russell C. Hibbeler
Publisher:
PEARSON
![Thermodynamics: An Engineering Approach](https://www.bartleby.com/isbn_cover_images/9781259822674/9781259822674_smallCoverImage.gif)
Thermodynamics: An Engineering Approach
Mechanical Engineering
ISBN:
9781259822674
Author:
Yunus A. Cengel Dr., Michael A. Boles
Publisher:
McGraw-Hill Education
![Control Systems Engineering](https://www.bartleby.com/isbn_cover_images/9781118170519/9781118170519_smallCoverImage.gif)
Control Systems Engineering
Mechanical Engineering
ISBN:
9781118170519
Author:
Norman S. Nise
Publisher:
WILEY
![Mechanics of Materials (MindTap Course List)](https://www.bartleby.com/isbn_cover_images/9781337093347/9781337093347_smallCoverImage.gif)
Mechanics of Materials (MindTap Course List)
Mechanical Engineering
ISBN:
9781337093347
Author:
Barry J. Goodno, James M. Gere
Publisher:
Cengage Learning
![Engineering Mechanics: Statics](https://www.bartleby.com/isbn_cover_images/9781118807330/9781118807330_smallCoverImage.gif)
Engineering Mechanics: Statics
Mechanical Engineering
ISBN:
9781118807330
Author:
James L. Meriam, L. G. Kraige, J. N. Bolton
Publisher:
WILEY