For the system of Problem 9.11, compute the fault current and voltages at the fault for the following faults at point F: (a) a bolted single line-to-ground fault; (b) a line- to-line fault through a fault impedance ZF = j0.05 per unit; (c) a double line-to- ground fault from phase B to C to ground, where phase B has a fault impedance ZF = j0.05 per unit, phase C also has a fault impedance ZF = j0.05 per unit, and the common line-to-ground fault impedance is ZG = j0.033 per unit.

Q: fault location

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A:

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Q: Problem 5 Thevenin equivalent sequence networks looking into the faulted bus of a power system are…

A: Given parameters are: Z1=j0.15,Z2=j0.15,Zo=j0.2E1=1∠0°pu

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Fault Analysis

In an electrical engineering system, a fault is an abnormal electric current flowing through the system, and fault analysis is the study of these faults. For instance, a short-circuit is a fault where the live wire touches the ground or neutral wire. If a circuit is interrupted by a failure of a current-carrying wire then an open circuit fault occurs. The open-circuit faults are also called series faults. One or more phases or ground may be involved in a three-phase fault or may occur only between two phases. Current flows into the earth in case of a ground fault or earth fault. For most situations, the prospective short circuit current of a fault that is predictable can be calculated. To limit the loss of service because of a failure, the protective devices can detect fault conditions and operate circuit breakers and also other devices. All phases equally can be affected in a poly-phase system which is known as symmetric electrical fault. The asymmetric fault becomes more complicated to analyze if only some phases are affected. By using methods such as symmetrical components, the power system analysis of these types of faults is often simplified. The main objective of power system protection is to design, detect, and interrupt power system faults.