For the reaction 4 A + 5 B → 2C+ 3 D, what is the magnitude of the rate of change for [D] when [A] is decreasing at 0.930 M/s?
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- 7:55 1 4 7 +/- Question 3 of 11 For the reaction A + 2 B 3 C + D, what is the magnitude of the rate of change for [D] when [C] is increasing at 4.6 M/s? 2 5 8 M/s 3 60 9 O Submit Tap here or pull up for additional resources XU x 100What is the Keq for the conversion of Glucose 6-Phosphate to Glucose 1-Phosphate if the phosphate transfer potential for Glucose 1-Phosphate and Glucose 6-Phosphate are -20.9 kJ/mol and -13.8 kJ/mol respectively? Select an answer and submit. For keyboard navigation, use the up/down arrow keys to select an answer. a 0.27 b 0.45 c 10.5 d 0.019 e 0.057 f 24.2 g 7.10 h 0.24 i 2477Determine the concentration of [Ser] at 75s at T=335K time (s) [Ser] at T=335 0.150 5 0.143 20 0.120 40 0.090 90 0.015 0.005 0.047 M 0.038 М 0.088 М
- The ΔG°′ value for glucose-1-phosphate is -20.9 kJ/mol. If glucose and phosphate are both at 4.8 mM, what is the equilibrium concentration of glucose-1-phosphate?C18H36O2(s) + 26O2(g) → 18CO2(g) + 18H2O(l) a) Compute the RER b) Determine the rate of energy expenditure at rest (RMR) if the rate of oxygen consumption 1.25 liter/minute. c) How much energy will be burned if the exercise will proceed for 1 hour?Calculate the overall ΔG° (report up to two decimal places) for the net reaction (see attached image). Answer: _____ kcal/mol Note: R = 1.98 x 10 -3 kcal/mol-K
- Use the concept of Hess' Law to determine AH for the process V 2X +Z given the following numbered processes: V 2 W AH1 W X + Y AH2 Z- 2Y AH3 ΔΗ+ ΔH +ΔΗ3 ΟΔΗ+ 2ΔΗ-ΔΗ3 ΟΔΗ+ 2ΔΗ2+ ΔΗ3 ΔΗ + ΔH,-ΔΗ3Calculate AG for the below balanced redox reaction as written. You may find a list of standard reduction potentials useful. 3 12 (s) + 2 Al (s) → 61 (aq) + 2 Al3+ (aq) O-4.24 x 102 kJ/mol O-6.48 x 102 kJ/mol O -2.12 x 102 kJ/mol O-1.27 x 103 kJ/mol O-6.37 x 102 kJ/molCalculate, or make a best estimate of, the unknown factors in the situations listed in Table 1. Table 1. Data for problem 1. To find Data (i) Ek [K+]out = 4 mM; [K+]in = 130 mM (ii) [Cl-]in [Cl-]out = 570 mM; ECl = -65 mV (iii) ECl [Cl-]out = 150 mM; [Cl-]in = 8 mM; in a mammal (iv) [Na+]in Overshoot of action potential = +35 mV; saline [Na+] = 112 mM (v) [K+]in Blood [K+] = 3.2 mM; undershoot of action potential = -87 mV (vi) ECa [Ca2+]out = 5.6 mM; free [Ca2+]in = 0.8 mM (vii) [K+]out [K+]in = 350 mM; Ek = -82 mV