For the reaction 20,H(g) + 70,(g) 4CO, (g) + 6H,0(g) (a) Predict the enthalpy of reaction from the average bond enthalpies in Table 9.4. - C2 Hie 으C-C - 2 (347)=6q니 K)/mol ZHH=12(4364)=5,236.845/mon o924.8 4002 4C-0=4(351) = 1404 kJ 10120 4c-0= 4 (799) = 319 bk) 6/20 3195.2/a120-H= 12(460)=5520 %3D 702 10-0 =7(142)= a94 KJ[mol 3195.20/mol b) Calculate the enthalpy of reaction (see Appendix 2) of the reactant and product molecules. 2(-64.7K/mo1) t 1(O) (-169.4k)/mol) (oks/mols →니(393-5k/mol) + b(- (-1574 KJ/mol) (-145 30a18 (169.41 -2855-4 K)/mol c) Compare the result with your answer for part (a) and (b).
For the reaction 20,H(g) + 70,(g) 4CO, (g) + 6H,0(g) (a) Predict the enthalpy of reaction from the average bond enthalpies in Table 9.4. - C2 Hie 으C-C - 2 (347)=6q니 K)/mol ZHH=12(4364)=5,236.845/mon o924.8 4002 4C-0=4(351) = 1404 kJ 10120 4c-0= 4 (799) = 319 bk) 6/20 3195.2/a120-H= 12(460)=5520 %3D 702 10-0 =7(142)= a94 KJ[mol 3195.20/mol b) Calculate the enthalpy of reaction (see Appendix 2) of the reactant and product molecules. 2(-64.7K/mo1) t 1(O) (-169.4k)/mol) (oks/mols →니(393-5k/mol) + b(- (-1574 KJ/mol) (-145 30a18 (169.41 -2855-4 K)/mol c) Compare the result with your answer for part (a) and (b).
Chemistry: The Molecular Science
5th Edition
ISBN:9781285199047
Author:John W. Moore, Conrad L. Stanitski
Publisher:John W. Moore, Conrad L. Stanitski
Chapter10: Fuels, Organic Chemicals, And Polymers
Section10.4: Alcohols And Their Oxidation Products
Problem 10.2PSP: Using a table of average bond enthalpies. Table 6.2 ( Sec. 6-6b), estimate the enthalpy change for...
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Question
The image with data, the left side is Appendix 2 (top left being inorganic and bottom left being organic)(I also highlighted the substances being used) and the right side is the table 9.4.
Did I do this problem properly?
Transcribed Image Text:15. For the reaction
2C,H,(g) + 70,(g)
4CO, (g) + 6H,0(g)
(a) Predict the enthalpy of reaction from the average bond enthalpies in Table 9.4.
2 C2 Hie
1404
3196
T0120 a UC-O=4 (799) = 319bk)Imol 5520
40z
4C-0 =4(351)= 1404 kJ (mul
694
%3D
5236-8 =20-C = 2(347)=16auk)/mol
10120
- 12 H-H=12(43lo4)=5,236.84lmon.co924.8
%3D
6t/20
10120
6924.8klmol 70z
Cbreaking of = 70-0 =7(142)= 994 kJ[mol 3195.20/mol)
3195.2/120-H= 12(460)= 5520k)/mol
अ१5.20/wo1
%3D
bondstofa))
(b) Calculate the enthalpy of reaction (see Appendix 2) of the reactant and product
molecules. 2(-64.7 ry lmoi) t 7(0) 4(393-5ky/mol) + 6(-24).8)
(-169:4k)/mol) CoKS/mols
(-1574 K)/mol)
(-1450-8 KJ{mal)
30a48
-(169.4/-
-2856.4 K)lmol)
(c) Compare the result with your answer for part (a) and (b).
Transcribed Image Text:Inorganic Substances
Table 9.4 Some Bond Enthalpies of Diatomic
Molecules* and Average Bond Enthalpies for
Substance
AH (kJ/mol)
AG (kJ/mol)
S° (J/K · mol)
Bonds in Polyatomic Molecules
249.4
230.1
160.95
Bond Enthalpy
(kJ/mol)
Bond Enthalpy
(kJ/mol)
O2(g)
Bond
Bond
205.0
H-H
436.4
C-I
-12.85.8
16. 3
-237.2
12,09
110 88
240
69.9
H-N
393
C-P
263
H,O(g)
-241.8
-228.6
H-O
460
C-S
255
188.7
H,0,()
H-S
368
C=S
477
-187.6
-110.5
-118.1
H-P
326
N-N
193
-137.3
CO,(g)
197.9
H-F
568.2
N=N
418
-393-5
-394.4
H-Cl
213.6
431.9
NEN
941.4
CO,(aq)
H-Br
366.1
-412.9
N-O
176
H-I
298.3
N=0
607
Organic Substances
C-H
414
0–0
142
AH: (kJ/mol) AG; (kJ/mol)
S° (J/K mol)
C-C
Substance
Formula
347
0=0
498.7
C=C
620
O-P
Acetic acid(I)
CH,COOH
-484.2
-389.45
159.8
502
CEC
812
0=S
469
Acetaldehyde(g) CH,CHO
-166.35
-139.08
264.2
C-N
276
P-P
197
Acetone(1)
CH,COCH3
-246.8
-153-55
198.7
C=N
615
P=P
489
Acetylene(g)
C,H,
226.6
209.2
200.8
EN
891
S-S
268
C,H6
49.04
124.5
172.8
Benzene(I)
351
S=S
352
Butane(g)
C,H10
-124.7
-15.7
310.0
745
F-F
156.9
C,H;OH
-276.98
-174.18
161.0
1076.5
Cl-Cl
Ethanol(I)
242.7
C-F
-168.5
282.7
450
Cl-F
Ethanol(g)
C,H,OH
-235.1
193
C-CI
-84.7
-32.89
229.5
338
Br-Br
Ethane(g)
C,H6
C-Br
192.5
276
I-I
68.1
219.5
151.0
52.3
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