For the reaction 20,H(g) + 70,(g) 4CO, (g) + 6H,0(g) (a) Predict the enthalpy of reaction from the average bond enthalpies in Table 9.4. - C2 Hie 으C-C - 2 (347)=6q니 K)/mol ZHH=12(4364)=5,236.845/mon o924.8 4002 4C-0=4(351) = 1404 kJ 10120 4c-0= 4 (799) = 319 bk) 6/20 3195.2/a120-H= 12(460)=5520 %3D 702 10-0 =7(142)= a94 KJ[mol 3195.20/mol b) Calculate the enthalpy of reaction (see Appendix 2) of the reactant and product molecules. 2(-64.7K/mo1) t 1(O) (-169.4k)/mol) (oks/mols →니(393-5k/mol) + b(- (-1574 KJ/mol) (-145 30a18 (169.41 -2855-4 K)/mol c) Compare the result with your answer for part (a) and (b).
Thermochemistry
Thermochemistry can be considered as a branch of thermodynamics that deals with the connections between warmth, work, and various types of energy, formed because of different synthetic and actual cycles. Thermochemistry describes the energy changes that occur as a result of reactions or chemical changes in a substance.
Exergonic Reaction
The term exergonic is derived from the Greek word in which ‘ergon’ means work and exergonic means ‘work outside’. Exergonic reactions releases work energy. Exergonic reactions are different from exothermic reactions, the one that releases only heat energy during the course of the reaction. So, exothermic reaction is one type of exergonic reaction. Exergonic reaction releases work energy in different forms like heat, light or sound. For example, a glow stick releases light making that an exergonic reaction and not an exothermic reaction since no heat is released. Even endothermic reactions at very high temperature are exergonic.
The image with data, the left side is Appendix 2 (top left being inorganic and bottom left being organic)(I also highlighted the substances being used) and the right side is the table 9.4.
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