Part C Predict the rate of change in the concentration of N₂O over this time interval. In other words, what is Express your answer using two significant figures. A[N₂0] At

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Chapter1: Chemical Foundations
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Please help, I'm stuck on part C and could use an explanation on how to solve it.

**Missed This?** Read Section 15.2 (Pages 632–636); Watch KCV 15.2, IWE 15.1.

**Consider the following reaction:**
\[ 2 \text{N}_2\text{O} (g) \rightarrow 2 \text{N}_2 (g) + \text{O}_2 (g) \]

---

**Part B**

In the first 13.0 seconds of the reaction, \(1.8 \times 10^{-2} \text{ mol of O}_2\) is produced in a reaction vessel with a volume of 0.310 L. What is the average rate of the reaction over this time interval?

**Express your answer using two significant figures.**

\[ \text{Rate} = 4.5 \times 10^{-3} \, \text{M} \cdot \text{s}^{-1} \]

Submit

Correct ✔️

The average rate of oxygen production was found using the equation:

\[ \text{Rate} = \frac{\Delta [\text{O}_2]}{\Delta t} \]

Where \([\text{O}_2]\) is the concentration of \(\text{O}_2\). Before finding the rate of the reaction, you had to find the concentration of \(\text{O}_2\) by dividing the moles of \(\text{O}_2\) by the volume of the vessel.

---

**Part C**

Predict the rate of change in the concentration of \(\text{N}_2\text{O}\) over this time interval. In other words, what is \(\frac{\Delta [\text{N}_2\text{O}]}{\Delta t}\)?

**Express your answer using two significant figures.**

\[ \frac{\Delta [\text{N}_2\text{O}]}{\Delta t} = \] \(\text{M} \cdot \text{s}^{-1}\)
Transcribed Image Text:**Missed This?** Read Section 15.2 (Pages 632–636); Watch KCV 15.2, IWE 15.1. **Consider the following reaction:** \[ 2 \text{N}_2\text{O} (g) \rightarrow 2 \text{N}_2 (g) + \text{O}_2 (g) \] --- **Part B** In the first 13.0 seconds of the reaction, \(1.8 \times 10^{-2} \text{ mol of O}_2\) is produced in a reaction vessel with a volume of 0.310 L. What is the average rate of the reaction over this time interval? **Express your answer using two significant figures.** \[ \text{Rate} = 4.5 \times 10^{-3} \, \text{M} \cdot \text{s}^{-1} \] Submit Correct ✔️ The average rate of oxygen production was found using the equation: \[ \text{Rate} = \frac{\Delta [\text{O}_2]}{\Delta t} \] Where \([\text{O}_2]\) is the concentration of \(\text{O}_2\). Before finding the rate of the reaction, you had to find the concentration of \(\text{O}_2\) by dividing the moles of \(\text{O}_2\) by the volume of the vessel. --- **Part C** Predict the rate of change in the concentration of \(\text{N}_2\text{O}\) over this time interval. In other words, what is \(\frac{\Delta [\text{N}_2\text{O}]}{\Delta t}\)? **Express your answer using two significant figures.** \[ \frac{\Delta [\text{N}_2\text{O}]}{\Delta t} = \] \(\text{M} \cdot \text{s}^{-1}\)
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