For the one electron system He*, the energies of the orbitals depend only on the value of the principle quantum number n (as is the case in hydrogen) such that we can say En = C x where C is a negative constant unique to He* (C = -2.18 × 10-18 J for H). An excited state electron in He* first emits a photon with wavelength 25.629 nm when it relaxes to the ground state. The electron subsequently absorbs a second photon with frequency 1.316x1016 Hz which is exactly enough energy to ionize the atom. a) What is the energy of an electron in the 1s orbital of He*?

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Chapter1: Chemical Foundations
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For the one electron system He*, the energies of the orbitals depend only on the value of the principle quantum
number n (as is the case in hydrogen) such that we can say En = C x where C is a negative constant unique to He*
(C = -2.18 × 10-18 J for H). An excited state electron in He* first emits a photon with wavelength 25.629 nm when it
relaxes to the ground state. The electron subsequently absorbs a second photon with frequency 1.316x1016 Hz which is
exactly enough energy to ionize the atom.
a) What is the energy of an electron in the 1s orbital of He*?
Transcribed Image Text:For the one electron system He*, the energies of the orbitals depend only on the value of the principle quantum number n (as is the case in hydrogen) such that we can say En = C x where C is a negative constant unique to He* (C = -2.18 × 10-18 J for H). An excited state electron in He* first emits a photon with wavelength 25.629 nm when it relaxes to the ground state. The electron subsequently absorbs a second photon with frequency 1.316x1016 Hz which is exactly enough energy to ionize the atom. a) What is the energy of an electron in the 1s orbital of He*?
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