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Curved arrows are used to illustrate the flow of electrons. Follow the arrows to predict the intermediate and product of reaction. Include all lone pairs. Use wedges and dashes to indicate stereochemistry. Ignore inorganic byproducts. pyridine, CI- 2013 Joh Drawing Q 1 1 1

Curved arrows are used to illustrate the flow of electrons. Follow the arrows to predict the intermediate and product of reaction. Include all lone pairs. Use wedges and dashes to indicate stereochemistry. Ignore inorganic byproducts. pyridine, CI- 2013 Joh Drawing Q 1 1 1

Chemistry
Chemistry
10th Edition
ISBN:9781305957404
Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Chapter1: Chemical Foundations
Section: Chapter Questions
Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...
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### Predicting Reaction Intermediate and Product #### Instructions Curved arrows are used to illustrate the flow of electrons. Follow the arrows to predict the intermediate and product of the reaction. Include all lone pairs. Use wedges and dashes to indicate stereochemistry. Ignore inorganic byproducts. #### Reaction Scheme 1. **Initial Reactants:** The initial reactants are shown in the diagram. It depicts a molecular structure with various atoms and bonds. Curved arrows indicate the movement of electrons from one atom to another, which leads to the formation of intermediate compounds. 2. **Reagent Addition:** Pyridine is added as a reagent. This will influence the electron movement and subsequent formation of intermediate products. 3. **Intermediate Formation:** As the reaction progresses, an intermediate compound is formed. The incoming pyridine affects the structure, which will be captured in the "Drawing" box (not shown in this transcription but implied to be detailed in a subsequent figure or diagram). 4. **Final Product Formation:** After the formation of the intermediate, the reaction continues leading to the final product, indicated in the last step. Chloride ion (Cl⁻) is also involved in this stage. Note: Ensure all lone pairs are included in the depiction of your structures, and use wedges and dashes to indicate stereochemistry appropriately (visual representation needed in actual application). #### Diagram Explanation - The initial molecular structure is the starting reactant. - Curved arrows show the flow of electrons, leading to bond formation or breaking. - The dashed rectangle labeled "Drawing" suggests the intermediate stage of the reaction. - Downward arrows denote the sequential step-by-step process of the reaction. This detailed explanation aids in understanding the electron movement and changes in molecular structure throughout the reaction process.
Transcribed Image Text:### Predicting Reaction Intermediate and Product #### Instructions Curved arrows are used to illustrate the flow of electrons. Follow the arrows to predict the intermediate and product of the reaction. Include all lone pairs. Use wedges and dashes to indicate stereochemistry. Ignore inorganic byproducts. #### Reaction Scheme 1. **Initial Reactants:** The initial reactants are shown in the diagram. It depicts a molecular structure with various atoms and bonds. Curved arrows indicate the movement of electrons from one atom to another, which leads to the formation of intermediate compounds. 2. **Reagent Addition:** Pyridine is added as a reagent. This will influence the electron movement and subsequent formation of intermediate products. 3. **Intermediate Formation:** As the reaction progresses, an intermediate compound is formed. The incoming pyridine affects the structure, which will be captured in the "Drawing" box (not shown in this transcription but implied to be detailed in a subsequent figure or diagram). 4. **Final Product Formation:** After the formation of the intermediate, the reaction continues leading to the final product, indicated in the last step. Chloride ion (Cl⁻) is also involved in this stage. Note: Ensure all lone pairs are included in the depiction of your structures, and use wedges and dashes to indicate stereochemistry appropriately (visual representation needed in actual application). #### Diagram Explanation - The initial molecular structure is the starting reactant. - Curved arrows show the flow of electrons, leading to bond formation or breaking. - The dashed rectangle labeled "Drawing" suggests the intermediate stage of the reaction. - Downward arrows denote the sequential step-by-step process of the reaction. This detailed explanation aids in understanding the electron movement and changes in molecular structure throughout the reaction process.
**Structural Representation of a Chemical Reaction Involving a Ketone and Thionyl Chloride** In the provided image, we see the structural representation of a chemical reaction involving a ketone and thionyl chloride. 1. **Reactants:** - **Chemical Structure at the Top:** - The molecule consists of a carbon chain attached to a hydroxyl group (OH). - The oxygen of the hydroxyl group is bonded to a sulfur (S), which is double-bonded to an oxygen (O) and bonded to two chlorine (Cl) atoms. 2. **Reaction Process:** - An arrow points downward, indicating the progression or direction of the chemical reaction. 3. **Products:** - **Chemical Structure at the Bottom:** - The product retains the original carbon structure. - The hydroxyl group now forms a new bond with the thionyl chloride, resulting in the formation of a chloride derivative and the release of hydrogen chloride as a by-product. The diagram visually demonstrates the chemical transformation that occurs when a ketone reacts with thionyl chloride, showcasing the new bonds formed and the molecular rearrangement resulting from the reaction.
Transcribed Image Text:**Structural Representation of a Chemical Reaction Involving a Ketone and Thionyl Chloride** In the provided image, we see the structural representation of a chemical reaction involving a ketone and thionyl chloride. 1. **Reactants:** - **Chemical Structure at the Top:** - The molecule consists of a carbon chain attached to a hydroxyl group (OH). - The oxygen of the hydroxyl group is bonded to a sulfur (S), which is double-bonded to an oxygen (O) and bonded to two chlorine (Cl) atoms. 2. **Reaction Process:** - An arrow points downward, indicating the progression or direction of the chemical reaction. 3. **Products:** - **Chemical Structure at the Bottom:** - The product retains the original carbon structure. - The hydroxyl group now forms a new bond with the thionyl chloride, resulting in the formation of a chloride derivative and the release of hydrogen chloride as a by-product. The diagram visually demonstrates the chemical transformation that occurs when a ketone reacts with thionyl chloride, showcasing the new bonds formed and the molecular rearrangement resulting from the reaction.
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