For the gas-phase reaction 250, +0,=2503. observed mole fractions for a certain equilibrium mixture at 1000 K and 1767 torr are Xso, = 0.290, Xo, = 0.220o, and Xso, =0.490. (i) Find partial pressure of each gas, Pso, : (torr), Poz : (torr), and Pso, : (torr). (ii) Find Kg : at 1000 K, assuming ideal gas. (iii) Find AG° : K]/mol at 1000 K, assuming ideal gas. (iv) Find Kg : at 1000 K Note:1 atm 76o torr 101325 Pa and R=82.06 m-atm-K-mol

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For the gas-phase reaction 250, + 02=2503. observed mole fractions for a certain equilibrium mixture at
1000 K and 1767 torr are Xso, = 0.290, Xo, = 0.22o, and Xso, =0.490.
(i) Find partial pressure of each gas, Pso,
: (torr), Poz
: (torr), and Pso;
: (torr).
(ii) Find Kg
: at 1000 K, assuming ideal gas.
(iii) Find AG°
* K)/mol at 1000 K, assuming ideal gas.
(iv) Find Ko
: at1000 K
Note:1 atm 760 torr 101325 Pa and R=82.06 m3-atm-K-mol
Transcribed Image Text:For the gas-phase reaction 250, + 02=2503. observed mole fractions for a certain equilibrium mixture at 1000 K and 1767 torr are Xso, = 0.290, Xo, = 0.22o, and Xso, =0.490. (i) Find partial pressure of each gas, Pso, : (torr), Poz : (torr), and Pso; : (torr). (ii) Find Kg : at 1000 K, assuming ideal gas. (iii) Find AG° * K)/mol at 1000 K, assuming ideal gas. (iv) Find Ko : at1000 K Note:1 atm 760 torr 101325 Pa and R=82.06 m3-atm-K-mol
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