Consider this equilibrium reaction at 400 K. Br, (g) + Cl, (g) = 2 BrCl(g) K. = 7.0 If the composition of the reaction mixture at 400 K is [BrCl] = 0.00684 M, [Br,] = 0.00193 M, and [Cl,] = 0.000354 M, %3D %3D what is the reaction quotient, Q? How is the reaction quotient related to the equilibrium constant, K, for this reaction? Oe < K, O e > K. O 0 = K,

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Consider this equilibrium reaction at 400 K.
Br, (g) + Cl, (g) = 2 BrCI(g)
Ke = 7.0
If the composition of the reaction mixture at 400 K is [BrCI]
what is the reaction quotient, Q?
= 0.00684 M, [Br,] = 0.00193 M, and [Cl,] = 0.000354 M,
%3D
How is the reaction quotient related to the equilibrium constant, K, for this reaction?
O0 < K,
O 0 > K,
0 = K,
Transcribed Image Text:Consider this equilibrium reaction at 400 K. Br, (g) + Cl, (g) = 2 BrCI(g) Ke = 7.0 If the composition of the reaction mixture at 400 K is [BrCI] what is the reaction quotient, Q? = 0.00684 M, [Br,] = 0.00193 M, and [Cl,] = 0.000354 M, %3D How is the reaction quotient related to the equilibrium constant, K, for this reaction? O0 < K, O 0 > K, 0 = K,
Expert Solution
Step 1

The equilibrium reaction taking place is given as,

=> Br2 (g) + Cl2 (g) ------> 2 BrCl (g)                                   Kc = 7.0 

Given : [BrCl] = 0.00684 M

[Br2 ] = 0.00193 M

And [Cl2 ] = 0.000354 M

 

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