A quantity of liquid methanol, CH3OH, is introduced into a rigid 3.00-L vessel, the vessel is sealed, and the temperature is raised to 500 K. At this temperature, the methanol vaporizes and decomposes according to the reaction CH₂OH(g) CO(g) + 2 H₂(g), Kc = 6.90 x10-2 If the concentration of H₂ in the equilibrium mixture is 0.426 M, what mass of methanol was initially introduced into the vessel?

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quantity of liquid methanol, CH3OH, is introduced into a rigid 3.00-L vessel, the vessel
is sealed, and the temperature is raised to 500 K. At this temperature, the methanol
vaporizes and decomposes according to the reaction
CH3OH(g) = CO(g) + 2 H₂(g), Kc = 6.90 ×10-2
If the concentration of H₂ in the equilibrium mixture is 0.426 M, what mass of methanol
was initially introduced into the vessel?
Transcribed Image Text:A quantity of liquid methanol, CH3OH, is introduced into a rigid 3.00-L vessel, the vessel is sealed, and the temperature is raised to 500 K. At this temperature, the methanol vaporizes and decomposes according to the reaction CH3OH(g) = CO(g) + 2 H₂(g), Kc = 6.90 ×10-2 If the concentration of H₂ in the equilibrium mixture is 0.426 M, what mass of methanol was initially introduced into the vessel?
Expert Solution
Step 1

First we need to calculate the initial molarity of methanol using the Kc value and equilibrium concentration of H2

Using concentration and volume, we can calculate moles of methanol. 

Then we can convert moles to mass using molar mass. 

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