A student ran the following reaction in the laboratory at 691 K: 2HI(g) =H₂(g) + I₂(g) When she introduced HI(g) at a pressure of 4.82 atm into a 1.00 L evacuated container, she found the equilibrium partial pressure of I₂(g) to be 0.506 atm. Calculate the equilibrium constant, Kp, she obtained for this reaction. Kp = ||
A student ran the following reaction in the laboratory at 691 K: 2HI(g) =H₂(g) + I₂(g) When she introduced HI(g) at a pressure of 4.82 atm into a 1.00 L evacuated container, she found the equilibrium partial pressure of I₂(g) to be 0.506 atm. Calculate the equilibrium constant, Kp, she obtained for this reaction. Kp = ||
Chemistry
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ISBN:9781305957404
Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Chapter1: Chemical Foundations
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
Transcribed Image Text:A student ran the following reaction in the
laboratory at 691 K:
2HI(g) =H₂(g) + I₂(9)
When she introduced HI(g) at a pressure
of 4.82 atm into a 1.00 L evacuated
container, she found the equilibrium partial
pressure of I₂(g) to be 0.506 atm.
Calculate the equilibrium constant, Kp, she
obtained for this reaction.
Kp = ||
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