Part A Phosgene (carbonyl chloride), COCI₂, is an extremely toxic gas that is used in manufacturing certain dyes and plastics. Phosgene can be produced by reacting carbon monoxide and chlorine gas at high temperatures: CO(g) + Cl₂(g) = COC1₂(g) Carbon monoxide and chlorine gas are allowed to react in a sealed vessel at 452 °C. At equilibrium, the concentrations were measured and the following results obtained: What is the equilibrium constant, Kp. of this reaction? Express your answer numerically. ▸ View Available Hint(s) Kp = Submit ΨΕ ΑΣΦΑ → Previous Answers Gas CO Cl₂ | COC, BO ? Partial Pressure (atm) 0.900 1.30 0.120

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**Calculating Equilibrium Constants**

The equilibrium constant, \( K \), of a reaction at a particular temperature is determined by the concentrations or pressures of the reactants and products at equilibrium.

For a gaseous reaction with the general form:

\[ aA + bB \rightleftharpoons cC + dD \]

the \( K_c \) and \( K_p \) expressions are given by:

\[ K_c = \frac{{[C]^c[D]^d}}{{[A]^a[B]^b}} \]

\[ K_p = \frac{{(P_C)^c(P_D)^d}}{{(P_A)^a(P_B)^b}} \]

The subscript c or p indicates whether \( K \) is expressed in terms of concentrations or pressures. Equilibrium-constant expressions do not include a term for any pure solids or liquids that may be involved since their composition does not change throughout the reaction. The standard state of a pure substance is the pure substance itself, and although the quantity may change, the sample remains pure. The constant value is incorporated into the value of \( K \), and does not need to be accounted for separately.

---

### Part A

Phosgene (carbonyl chloride), \( \text{COCl}_2 \), is an extremely toxic gas used in manufacturing certain dyes and plastics. Phosgene can be produced by reacting carbon monoxide and chlorine gas at high temperatures:

\[ \text{CO}(g) + \text{Cl}_2(g) \rightleftharpoons \text{COCl}_2(g) \]

Carbon monoxide and chlorine gas are allowed to react in a sealed vessel at \( 452 \, ^\circ \text{C} \). At equilibrium, the concentrations were measured and the following results obtained:

| Gas   | Partial Pressure (atm) |
|-------|------------------------|
| CO    | 0.900                  |
| \( \text{Cl}_2 \)  | 1.30                  |
| \( \text{COCl}_2 \) | 0.120                  |

What is the equilibrium constant, \( K_p \), of this reaction?

Express your answer numerically.

[View Available Hint(s)]

\( K_p = \)

---

(There is also an interactive input box to enter the \( K_p \) value, accompanied by options to format the text and a submit button.)
Transcribed Image Text:**Calculating Equilibrium Constants** The equilibrium constant, \( K \), of a reaction at a particular temperature is determined by the concentrations or pressures of the reactants and products at equilibrium. For a gaseous reaction with the general form: \[ aA + bB \rightleftharpoons cC + dD \] the \( K_c \) and \( K_p \) expressions are given by: \[ K_c = \frac{{[C]^c[D]^d}}{{[A]^a[B]^b}} \] \[ K_p = \frac{{(P_C)^c(P_D)^d}}{{(P_A)^a(P_B)^b}} \] The subscript c or p indicates whether \( K \) is expressed in terms of concentrations or pressures. Equilibrium-constant expressions do not include a term for any pure solids or liquids that may be involved since their composition does not change throughout the reaction. The standard state of a pure substance is the pure substance itself, and although the quantity may change, the sample remains pure. The constant value is incorporated into the value of \( K \), and does not need to be accounted for separately. --- ### Part A Phosgene (carbonyl chloride), \( \text{COCl}_2 \), is an extremely toxic gas used in manufacturing certain dyes and plastics. Phosgene can be produced by reacting carbon monoxide and chlorine gas at high temperatures: \[ \text{CO}(g) + \text{Cl}_2(g) \rightleftharpoons \text{COCl}_2(g) \] Carbon monoxide and chlorine gas are allowed to react in a sealed vessel at \( 452 \, ^\circ \text{C} \). At equilibrium, the concentrations were measured and the following results obtained: | Gas | Partial Pressure (atm) | |-------|------------------------| | CO | 0.900 | | \( \text{Cl}_2 \) | 1.30 | | \( \text{COCl}_2 \) | 0.120 | What is the equilibrium constant, \( K_p \), of this reaction? Express your answer numerically. [View Available Hint(s)] \( K_p = \) --- (There is also an interactive input box to enter the \( K_p \) value, accompanied by options to format the text and a submit button.)
**Understanding Equilibrium Constants**

The equilibrium constant, \( K \), of a reaction at a particular temperature is determined by the concentrations or pressures of the reactants and products at equilibrium.

**For a gaseous reaction with the general form:**

\[ aA + bB \rightleftharpoons cC + dD \]

**The expressions for \( K_c \) and \( K_p \) are:**

\[ K_c = \frac{[C]^c[D]^d}{[A]^a[B]^b} \]

\[ K_p = \frac{(P_C)^c(P_D)^d}{(P_A)^a(P_B)^b} \]

Here, the subscript \( c \) or \( p \) indicates whether \( K \) is expressed in terms of concentrations or pressures. Equilibrium-constant expressions do not include terms for pure solids or liquids, as their composition does not change throughout the reaction. The standard state of a pure substance is itself, although the quantity may change. The constant value is incorporated into \( K \) and does not need separate accounting.

---

**Deriving Concentrations from Data**

In Part A, equilibrium pressures were provided and could be used directly in the formula for \( K \). However, in Part B, you will be given initial concentrations and only one equilibrium concentration. Use this data to find all three equilibrium concentrations before applying the formula for \( K \).

**Part B**

A reaction was conducted in a sealed vessel at 740°C:

\[ \text{H}_2(g) + \text{I}_2(g) \rightleftharpoons 2\text{HI}(g) \]

* Initial concentrations: \([H_2] = 3.00 \, M\) and \([I_2] = 2.15 \, M\)
* Equilibrium concentration of \([I_2]\) is 0.0700 \( M \).

**Task**

Calculate the equilibrium constant, \( K_c \), for the reaction at this temperature. Provide your answer numerically.
Transcribed Image Text:**Understanding Equilibrium Constants** The equilibrium constant, \( K \), of a reaction at a particular temperature is determined by the concentrations or pressures of the reactants and products at equilibrium. **For a gaseous reaction with the general form:** \[ aA + bB \rightleftharpoons cC + dD \] **The expressions for \( K_c \) and \( K_p \) are:** \[ K_c = \frac{[C]^c[D]^d}{[A]^a[B]^b} \] \[ K_p = \frac{(P_C)^c(P_D)^d}{(P_A)^a(P_B)^b} \] Here, the subscript \( c \) or \( p \) indicates whether \( K \) is expressed in terms of concentrations or pressures. Equilibrium-constant expressions do not include terms for pure solids or liquids, as their composition does not change throughout the reaction. The standard state of a pure substance is itself, although the quantity may change. The constant value is incorporated into \( K \) and does not need separate accounting. --- **Deriving Concentrations from Data** In Part A, equilibrium pressures were provided and could be used directly in the formula for \( K \). However, in Part B, you will be given initial concentrations and only one equilibrium concentration. Use this data to find all three equilibrium concentrations before applying the formula for \( K \). **Part B** A reaction was conducted in a sealed vessel at 740°C: \[ \text{H}_2(g) + \text{I}_2(g) \rightleftharpoons 2\text{HI}(g) \] * Initial concentrations: \([H_2] = 3.00 \, M\) and \([I_2] = 2.15 \, M\) * Equilibrium concentration of \([I_2]\) is 0.0700 \( M \). **Task** Calculate the equilibrium constant, \( K_c \), for the reaction at this temperature. Provide your answer numerically.
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