The equilibrium constant for the following reaction is 6.47×10-2 at 396 °C.so,Cl2(9)SO2(g) + Cl2(g)K = 6.47x10-2 at 396 °CCalculate the equilibrium constant for the following reactions at 396 °C.(a) sO2(g) + Cl2(g)so2Cl2(g)K =(b) 2 SO2C12(g)2 SO2(g) + 2 Cl2(g)K =

given, for a reaction: SO2Cl2(g) ⇔ SO2(g) + Cl2(g) 1 equilibrium constant, K =…

The equilibrium constant for the following reaction is 6.47x10-2 at 396 °C. So2Cl2(g) sO2(g) + Cl2(g) K = 6.47x1o-2 at 396 °C Calculate the equilibrium constant for the following reactions at 396 °C. (a) SO2(g) + Cl2(g) so,Cl2(g) K = (b) 2 SO2CI2(g) 2 SO2(g) + 2 Cl2(g) K =

The equilibrium constant for the following reaction is 6.47x10-2 at 396 °C. So2Cl2(g) sO2(g) + Cl2(g) K = 6.47x1o-2 at 396 °C Calculate the equilibrium constant for the following reactions at 396 °C. (a) SO2(g) + Cl2(g) so,Cl2(g) K = (b) 2 SO2CI2(g) 2 SO2(g) + 2 Cl2(g) K =

Chemistry

10th Edition

ISBN:9781305957404

Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Chapter1: Chemical Foundations

Section: Chapter Questions

Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...

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Question

The equilibrium constant for the following reaction is 6.47×10-2 at 396 °C.
so,Cl2(9)
SO2(g) + Cl2(g)
K = 6.47x10-2 at 396 °C
Calculate the equilibrium constant for the following reactions at 396 °C.
(a) sO2(g) + Cl2(g)
so2Cl2(g)
K =
(b) 2 SO2C12(g)
2 SO2(g) + 2 Cl2(g)
K =

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