For her electronics class, Gabriella configures a circuit as shown in the figure. Find the following. (Assume C₁ = 30.0 μF and C₂ = 3.33 μF.) 6.00 uF C₁ μF C₂ µF 9.00 V (a) the equivalent capacitance (in µF) HF (b) the charge on each capacitor (in µC) C₁ (left) C₁ (right) C₂ 6.00 μF capacitor C₁ μF μC μC HC μC Ⓡ (c) the potential difference across each capacitor (in V) C₁ (left) C₁ (right) C₂ 6.00 μF capacitor V V V V

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Chapter1: Units, Trigonometry. And Vectors
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For her electronics class, Gabriella configures a circuit as shown in the figure. Find the following. (Assume C₁ = 30.0 μF and C₂ = 3.33 μF.)
6.00 µF
C₁ μF
C₂ μF
+
9.00 V
(a) the equivalent capacitance (in µF)
μF
(b) the charge on each capacitor (in µC)
C₁ (left)
C₁ (right)
C₂
6.00 μF capacitor
C₁ µF
9999
(c) the potential difference across each capacitor (in V)
C₁ (left)
C₁ (right)
C₂
6.00 μF capacitor
V
V
V
V
Transcribed Image Text:For her electronics class, Gabriella configures a circuit as shown in the figure. Find the following. (Assume C₁ = 30.0 μF and C₂ = 3.33 μF.) 6.00 µF C₁ μF C₂ μF + 9.00 V (a) the equivalent capacitance (in µF) μF (b) the charge on each capacitor (in µC) C₁ (left) C₁ (right) C₂ 6.00 μF capacitor C₁ µF 9999 (c) the potential difference across each capacitor (in V) C₁ (left) C₁ (right) C₂ 6.00 μF capacitor V V V V
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