Consider the circuit shown in the figure, with C, = 5.42 µF and C, = 7.14 µF. 6.00 µF 2.00 µF C2 + 90.0 V (a) Find the equivalent capacitance (in µF) of the system. HF (b) Find the charge (in µC) on each capacitor. 5.42 µF capacitor 6.00 µF capacitor 7.14 µF capacitor 2.00 µF capacitor (c) Find the potential difference (in V) on each capacitor. 5.42 µF capacitor V 6.00 µF capacitor V 7.14 µF capacitor V 2.00 µF capacitor V 을 일
Consider the circuit shown in the figure, with C, = 5.42 µF and C, = 7.14 µF. 6.00 µF 2.00 µF C2 + 90.0 V (a) Find the equivalent capacitance (in µF) of the system. HF (b) Find the charge (in µC) on each capacitor. 5.42 µF capacitor 6.00 µF capacitor 7.14 µF capacitor 2.00 µF capacitor (c) Find the potential difference (in V) on each capacitor. 5.42 µF capacitor V 6.00 µF capacitor V 7.14 µF capacitor V 2.00 µF capacitor V 을 일
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Transcribed Image Text:Consider the circuit shown in the figure, with C, = 5.42 µF and C, = 7.14 µF.
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6.00 µF
2.00 µF
C2
+
90.0 V
(a) Find the equivalent capacitance (in µF) of the system.
(b) Find the charge (in µC) on each capacitor.
5.42 µF capacitor
6.00 µF capacitor
7.14 µF capacitor
2.00 µF capacitor
(c) Find the potential difference (in V) on each capacitor.
5.42 µF capacitor
V
6.00 µF capacitor
V
7.14 µF capacitor
V
2.00 µF capacitor
V
(d) Find the total energy (in mJ) stored by the group.
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