(a) What is the equivalent capacitance (in pF) of all the capacitors in the entire circult? uF (b) What is the charge (in pC) stored by each capacitor? right 19.20 uF capacitor left 19.20 uF capacitor 13.20 uF capacitor UC 6.00 uF capacitor (c) What is the potential difference (in V) across each capacitor? (Enter the gnitudes.) V. right 19.20 uF capacitor left 19.20 uF capacitor 13.20 uF capacitor 6.00 µF capacitor V

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Chapter1: Units, Trigonometry. And Vectors
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Question
The circuit in the figure below contains a 9.00
battery and four capacitors. The two capacitors on the left and right both have same capacitance of C, = 19.20 µF. The capacitors in the top two branches have
capacitances of 6.00 pF and C, = 13.20 pF.
6.00 uF
9.00 V
(a) What is the equivalent capacitance (in uF) of all the capacitors in the entire circult?
(b) What is the charge (in uC) stored by each capacitor?
right 19.20 uF capacitor
pC
left 19.20 pF capacitor
pC
13.20 pF capacitor
6.00 µF capacitor
(c) What is the potential difference (in V) across each capacitor? (Enter the
gnitudes.)
right 19.20 pF capacitor
V
left 19.20 uF capacitor
13.20 µF capacitor
V
6.00 µF capacitor
V
Transcribed Image Text:The circuit in the figure below contains a 9.00 battery and four capacitors. The two capacitors on the left and right both have same capacitance of C, = 19.20 µF. The capacitors in the top two branches have capacitances of 6.00 pF and C, = 13.20 pF. 6.00 uF 9.00 V (a) What is the equivalent capacitance (in uF) of all the capacitors in the entire circult? (b) What is the charge (in uC) stored by each capacitor? right 19.20 uF capacitor pC left 19.20 pF capacitor pC 13.20 pF capacitor 6.00 µF capacitor (c) What is the potential difference (in V) across each capacitor? (Enter the gnitudes.) right 19.20 pF capacitor V left 19.20 uF capacitor 13.20 µF capacitor V 6.00 µF capacitor V
Expert Solution
Step

here we have given the capacitance of four capacitor

C1=19.20, C2=13.20

AND combination of capacitor 6 micro faraday and 13.20 micro faraday in parallel and then all in series combination

C parallel= C1+C2+C3+C4

1/Cseries=1/C1+1/C2+1/C3+1/C4

Q=CV

V=Q/C

these formula we will used to solve the question

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