A C=2.8pf parallel plate capacitor has a plate area of A and a plate separation of d. The capacitor is charged to a voltage V=10.4V and remains connected to the battery. The plate separation is then increased by 29%. Determine the change in the stored energy (in pJ ).

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Chapter1: Units, Trigonometry. And Vectors
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A \( C = 2.8 \, \text{pF} \) parallel plate capacitor has a plate area of \( A \) and a plate separation of \( d \). The capacitor is charged to a voltage \( V = 10.4 \, \text{V} \) and remains connected to the battery. The plate separation is then increased by 29%. Determine the change in the stored energy (in \( \text{pJ} \)).
Transcribed Image Text:A \( C = 2.8 \, \text{pF} \) parallel plate capacitor has a plate area of \( A \) and a plate separation of \( d \). The capacitor is charged to a voltage \( V = 10.4 \, \text{V} \) and remains connected to the battery. The plate separation is then increased by 29%. Determine the change in the stored energy (in \( \text{pJ} \)).
Expert Solution
Step 1

Given value---

  • C = 2.8 pF.
  • V = 10.4 V.

We have to find---

  • The plate separation is then increased by 29%. Determine the change in the stored energy (in pJ) ?
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