A capacitor C1=3μFC1=3μF is connected across a 20V battery. The battery is removed and the capacitor is reconnected to another capacitor C2=8μFC2=8μF. What are the final charges and potential differences for the capacitors?
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A capacitor C1=3μFC1=3μF is connected across a 20V battery. The battery is removed and the capacitor is reconnected to another capacitor C2=8μFC2=8μF. What are the final charges and potential differences for the capacitors?
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- Where a 2.7 V battery is connected to a network of capacitors with C1 = 54 F, C2 = 63 F, and C3 = 45 F. What is the equivalent capacitance connected to the battery? (in F) 162 F 17.7 F 36.0 F 80.2 FA 1.4 μF capacitor is charged to a potential difference of 14.0 V. The wires connecting the capacitor to the battery are then disconnected from the battery and connected across a second, initially uncharged, capacitor. The potential difference across the 1.4 µF capacitor then drops to 6 V. What is the capacitance of the second capacitor? uFIn the figure the capacitances are C₁ = 1.4 µF and C₂ = 2.8 µF, and both capacitors are charged to a potential difference of V = 150 V but with opposite polarity as shown. Switches S₁ and S₂ are now closed. (a) What is now the potential difference between points a and b? What now is the charge on capacitor (b) 1 and (c) 2? C₁ C₂
- Two identical capacitors Ca and Cb each of capacitance 2.70 μF are connected in parallel across a CONSTANT total electric potential difference of 510 V. A dielectric slab of dielectric constant 6.90 can fill Ca and is slowly inserted into that capacitor.What is the change in charge, ΔQa, on Ca when the dielectric is added to Ca?You have two parallel plate capacitors, C 1a = 10 nF and C 2a = 20 nF, each with the same area of 2 m^2 that is filled with a dielectric material that is 1 mm thick. a) If the capacitors are connected in series vs parallel, which provides more total capacitance? b) What is the difference in total energy if the capacitors are connected in series vs. parallel? c) What dielectric material would you use in order to make the total capacitance of the capacitors connected in series equal to if they were connected in parallel? Help...An engineer has three different capacitors of unknown capacitance. She labels them C₁, C₂, and C3. First, she connects C₁ to a battery, and the charge on C₁ is q₁ = 32.2 µC. Then, she disconnects and discharges C₁, and connects it in series with C₂. When she connects this series combination of C₂ and C₁ across the battery, the charge on C₁ is 9₂ = 23.6 µC. The engineer disconnects the circuit and discharges both capacitors. Next, she connects C3, C₁, and the battery in series, which results in a charge on C₁ of 93 = 25.4 µC. If, after being disconnected and discharged, she connects C₁, C₂, and C3 in series with the battery, what is the charge on C₁ (in μC)? X