A capacitor (25-pF) is charged to 50 V. Another capacitor C is charged to 20 V. Both capacitors are connected to each other, with the two positive plates connected and the two negative plates connected. The final potential difference across the 25-pF capacitor is 36 V. What is the value of the capacitance of C?

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A: Given : Q = 4 µC = 4 x 10-6 C V = 80 V

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Combination of Capacitors

The connection of capacitors can be established in a circuit in two ways.