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A lab tech builds a circuit as shown in the figure. Find the following. (Assume C₁ = 33.0 μF and C₂ = 2.93 µF.) 6.00 uF C₁ µF C₂ µF 9.00 V (a) the equivalent capacitance (in µF) 5.79 HF 6.00 μF capacitor (b) the charge on each capacitor (in μC) C₂ (left) C₂ (right) C₂ C₁ µF ✓ HC ✓ HC 52.11 52.11 26.37 Note that the charge on each capacitor in the series is the same as the charge on the equivalent capacitor. Apply the relationship Q = CAV to find the charge. For the two capacitors in parallel, you will first need to determine the potential difference across the parallel combination, then calculate the charges on the individual capacitors. μC 52.11 x Note that the charge on each capacitor in the series is the same as the charge on the equivalent capacitor. Apply the relationship Q = CAV to find the charge. For the two capacitors in parallel, you will first need to determine the potential difference across the parallel combination, then calculate the charges on the individual capacitors. μC (c) the potential difference across each capacitor (in V) C₂ (left) C₂ (right) C₂ 6.00 uF capacitor V V V V

A lab tech builds a circuit as shown in the figure. Find the following. (Assume C₁ = 33.0 μF and C₂ = 2.93 µF.) 6.00 uF C₁ µF C₂ µF 9.00 V (a) the equivalent capacitance (in µF) 5.79 HF 6.00 μF capacitor (b) the charge on each capacitor (in μC) C₂ (left) C₂ (right) C₂ C₁ µF ✓ HC ✓ HC 52.11 52.11 26.37 Note that the charge on each capacitor in the series is the same as the charge on the equivalent capacitor. Apply the relationship Q = CAV to find the charge. For the two capacitors in parallel, you will first need to determine the potential difference across the parallel combination, then calculate the charges on the individual capacitors. μC 52.11 x Note that the charge on each capacitor in the series is the same as the charge on the equivalent capacitor. Apply the relationship Q = CAV to find the charge. For the two capacitors in parallel, you will first need to determine the potential difference across the parallel combination, then calculate the charges on the individual capacitors. μC (c) the potential difference across each capacitor (in V) C₂ (left) C₂ (right) C₂ 6.00 uF capacitor V V V V

College Physics
College Physics
11th Edition
ISBN:9781305952300
Author:Raymond A. Serway, Chris Vuille
Publisher:Raymond A. Serway, Chris Vuille
Chapter1: Units, Trigonometry. And Vectors
Section: Chapter Questions
Problem 1CQ: Estimate the order of magnitude of the length, in meters, of each of the following; (a) a mouse, (b)...
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A lab tech builds a circuit as shown in the figure. Find the following. (Assume C₁ = 33.0 μF and C₂ = 2.93 μF.) C₁ μF 6.00 uF C₂ μF 6.00 μF capacitor 9.00 V (a) the equivalent capacitance (in µF) 5.79 ✓ µF (b) the charge on each capacitor (in µC) C₁ (left) ✓ C₁ (right) C₁ μF HC μC 52.11 52.11 26.37 X Note that the charge on each capacitor in the series is the same as the charge on the equivalent capacitor. Apply the relationship Q = CAV to find the charge. For the two capacitors in parallel, you will first need to determine the potential difference across the parallel combination, then calculate the charges on the individual capacitors. μC 52.11 X Note that the charge on each capacitor in the series is the same as the charge on the equivalent capacitor. Apply the relationship Q = CAV to find the charge. For the two capacitors in parallel, you will first need to determine the potential difference across the parallel combination, then calculate the charges on the individual capacitors. μC (c) the potential difference across each capacitor (in C₁ (left) C₁ (right) C₂ 6.00 μF capacitor V V V V
Transcribed Image Text:A lab tech builds a circuit as shown in the figure. Find the following. (Assume C₁ = 33.0 μF and C₂ = 2.93 μF.) C₁ μF 6.00 uF C₂ μF 6.00 μF capacitor 9.00 V (a) the equivalent capacitance (in µF) 5.79 ✓ µF (b) the charge on each capacitor (in µC) C₁ (left) ✓ C₁ (right) C₁ μF HC μC 52.11 52.11 26.37 X Note that the charge on each capacitor in the series is the same as the charge on the equivalent capacitor. Apply the relationship Q = CAV to find the charge. For the two capacitors in parallel, you will first need to determine the potential difference across the parallel combination, then calculate the charges on the individual capacitors. μC 52.11 X Note that the charge on each capacitor in the series is the same as the charge on the equivalent capacitor. Apply the relationship Q = CAV to find the charge. For the two capacitors in parallel, you will first need to determine the potential difference across the parallel combination, then calculate the charges on the individual capacitors. μC (c) the potential difference across each capacitor (in C₁ (left) C₁ (right) C₂ 6.00 μF capacitor V V V V
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