For the arrangement of capacitors in problem 10, find the equivalent capacitance in μF (microfarads) using C1 = 13.7 μF (microfarads) , C2 = (0.500) C1, and C3 = (0.400) C1 (Answer in 5 sig. figs.)
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- Two capacitors give an equivalent capacitance of 9.68 pF when connected in parallel and an equivalent capacitance of 1.8 pF when connected in series. What is the capacitance in pF of the capacitor with the larger capacitance? Round your answer to 2 decimal places.For problem 34 find U1 in mJ for C1 using capacitance values of C1 = 36.0 μF (microfarads) and C2 = (0.500) C1. All other values are the same as in the text. (Answer in 5 sig. figs.)There are two capacitors. If they are connected in parallel, the equivalent electricity capacity is 9.00 pF, and if they are connected in series, the equivalent electricity capacity is 2.00 pF. Find the capacitance of each capacitor.
- A capacitor with capacitance 5.75 μF is connected to a(n) 5.75-V battery. (a) Find the charge on the capacitor in coulombs. 3.30-5 С (b) What voltage battery would be required to store 8.00 x 10-5 C on the capacitor? 6.95 X Your response differs from the correct answer by more than 10%. Double check your calculations. V13 Dry air is a pretty decent insulator; it has a very high resistivity of 3 × 105 2 · m. Consider a capacitor that has square plates 15 cm on a side, separated by 0.8 mm of dry air. The capacitor is charged such that it has a potential of 320 V between the plates.13 Dry air is a pretty decent insulator; it has a very high resistivity of 3 × 10º Q · m. Consider a capacitor that has square plates 15 cm on a side, separated by 0.8 mm of dry air. The capacitor is charged such that it has a potential of 320 V between the plates.
- Problem 7: Capacitor C, is initially charged to V, and capacitor C, is initially charged to V. The capacitors are then connected to each other, positive terminal to positive terminal and negative terminal to negative terminal. If C = 16 µF with initial voltage of 25 V, and capacitor C2 = 13 µF is charged to 7 V. What is the final voltage, in volts, across C;? V =Two Capacitors are in series. C1=304 μF and C2=295 μF. What is the equivalent capacitance of the system measured in μF ? Enter a number and assume units of micro Farads.Find the following. (In the figure, use C, = 31.00 µF and C, = 25.00 µF.) 6.00 µF C2 µF CµF 9.00 V (a) the equivalent capacitance of the capacitors in the figure above uF (b) the charge on each capacitor on the right 31.00-µF capacitor on the left 31.00-µF capacitor μC on the 25.00-µF capacitor on the 6.00-µF capacitor
- Three capacitors are connected in series as shown in the figure. The capacitances are C1 = 5.7 μF, and C2 = 9.8 μF, C3 is unknown, and the charge stored in each capacitor is Q = 8.5 μC. a) Express the capacitance C of a capacitor in terms of charge Q and voltage ΔV on it. Part (b) Apply the above formula to capacitor C1 to find an expression for the potential difference ΔV12 across it. Part (c) Express the potential difference ΔV12 through potentials V1 and V2 where V1 and V2 are the potentials measured in the wires 1 and 2, respectively, relative to the negative side of the battery. Part (d) Calculate V2 in V given V1 = 9 V. Part (e) Repeat the above procedure for capacitor C2 and calculate the potential at point 3, V3 in V.Two capacitors provide an equivalent capacitance of 16.00 μμF when connected in parallel and 4.00 μμF when connected in series. 1)What is the smaller capacitance of the capacitors? If both capacitors have the same capacitance, enter this value. (Express your answer to three significant figures.) 2)What is the larger capacitance of the capacitors? If both capacitors have the same capacitance, enter this value. (Express your answer to three significant figures.)Capacitance Problem 7: Consider a spherical metal shell of radius R in empty space. Part (b) Calculate the capacitance, in picofarads, of such a conductor with a radius of R = 0.058 m.