Find the equivalent capacitance in pF for the dielectric capacitor in problem 48 using values of κ1 = 6.5 and κ2 = 12.0. All other parameters in the problem are same as in the text. (Answer in 5 sig. figs.) 48 Figure 25-47 shows a parallel-plate capacitor with a plate area A= 5.56 cm² and separation d = 5.56mm. The left half of the gap is filledwith material of dielectric constantK₁ = 7.00; the right half is filled withmaterial of dielectric constant ₂12.0. What is the capacitance?=A/2-K1A/2K2Figure 25-47 Problem 48. QUESTION 4Find the equivalent capacitance in pF for thedielectric capacitor in problem 25.48 using valuesof K₁ = 6.5 and K2 = 12.0. All other parameters inthe problem are as in the text. (5 sig. figs.)

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Answered: QUESTION 4 Find the equivalent…

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QUESTION 4 Find the equivalent capacitance in pF for the dielectric capacitor in problem 25.48 using values of K₁ = 6.5 and K2 = 12.0. All other parameters in the problem are as in the text. (5 sig. figs.)