QUESTION 4 Find the equivalent capacitance in pF for the dielectric capacitor in problem 25.48 using values of K₁ = 6.5 and K2 = 12.0. All other parameters in the problem are as in the text. (5 sig. figs.)

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Find the equivalent capacitance in pF for the dielectric capacitor in problem 48 using values of κ1 = 6.5 and κ2 = 12.0. All other parameters in the problem are same as in the text. (Answer in 5 sig. figs.)
48 Figure 25-47 shows a parallel-
plate capacitor with a plate area A
= 5.56 cm² and separation d = 5.56
mm. The left half of the gap is filled
with material of dielectric constant
K₁ = 7.00; the right half is filled with
material of dielectric constant ₂
12.0. What is the capacitance?
=
A/2-
K1
A/2
K2
Figure 25-47 Problem 48.
Transcribed Image Text:48 Figure 25-47 shows a parallel- plate capacitor with a plate area A = 5.56 cm² and separation d = 5.56 mm. The left half of the gap is filled with material of dielectric constant K₁ = 7.00; the right half is filled with material of dielectric constant ₂ 12.0. What is the capacitance? = A/2- K1 A/2 K2 Figure 25-47 Problem 48.
QUESTION 4
Find the equivalent capacitance in pF for the
dielectric capacitor in problem 25.48 using values
of K₁ = 6.5 and K2 = 12.0. All other parameters in
the problem are as in the text. (5 sig. figs.)
Transcribed Image Text:QUESTION 4 Find the equivalent capacitance in pF for the dielectric capacitor in problem 25.48 using values of K₁ = 6.5 and K2 = 12.0. All other parameters in the problem are as in the text. (5 sig. figs.)
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