Following a week-long hospital training program, 50 hospital administrators made amean score of 74 on a test administered as part of the evaluation of the training programwith a sample standard deviation of 10. Use a 0.05 significance level to test the claimthat the population mean is greater than 70. State your conclusion in the conclusion inthe context of the problem. Support your conclusion with your test statistic, criticalvalue, p-value and confidence interval.toboja ogollos indtomis lo trots oT (9-(d=botndinsaib vilsamobute agolloo botoolsz vimolStnomsivsbog order toraigmes of

We have given thatMean(µ) = 70Sample size (n) = 50Sample mean (x̅) = 74Standard deviations (s) =…

Answered: Following a week-long hospital training…

MATLAB: An Introduction with Applications

6th Edition

ISBN:9781119256830

Author:Amos Gilat

Publisher:Amos Gilat

Chapter1: Starting With Matlab

Section: Chapter Questions

Problem 1P

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In a survey, 28 people were asked how much they spent on their child's last birthday gift. The results were roughly bell-shaped with a mean of $44 and standard deviation of $10. Estimate how much a typical parent would spend on their child's birthday gift (use a 80% confidence level). Give your answers to one decimal place. Provide the point estimate and margin or error. +
NebNas manages the credit department for a grocery store chain in the province, and she would like to determine whether the mean monthly balance of credit card holders is equal to $95. A random sample of 100 accounts indicated that the mean owed is $101.5 with a sample standard deviation of $25.6. If she wanted to test whether the mean balance is different from $95 and decided to reject the null hypothesis, what will be the p-value of the test?
The internal consistency of a high stakes academic exam is calculated to be 0.94. 1. What percent of the score is due to true score? 2. What percent is due to random error? 3. Is 0.94 considered a strong, moderate or low measure of reliability? Why?
Your friend claims that he heard that the average number of Facebook friends was 300 in 2010. You suspect that that the average has increased. 1. At the .05 significance level, what decision do you make? 2. Write a conclusion for your friend explaining your decision without using statistical symbols.
Please find test statistic and p value. Thank you.
Microsoft Word -... # The average number of accidents at controlled intersections per year is 5.4. Is this average more for intersections with cameras installed? The 47 randomly observed intersections with cameras installed had an average of 5.9 accidents per year and the standard deviation was 1.08. What can be concluded at the a = 0.01 level of significance? a. For this study, we should use t-test for a population mean b. The null and alternative hypotheses would be: Ho: V = H₁: > 5.4 c. The test statistic t = 3.174 (please show your answer to 3 decimal places.) d. The p-value = (Please show your answer to 4 decimal places.) e. The p-value is ? a f. Based on this, we should g. Thus, the final conclusion is that ... 80 F3 V 5.4 Select an answer the null hypothesis. O The data suggest that the populaton mean is significantly more than 5.4 at a = 0.01, so there is statistically significant evidence to conclude that the population mean number of accidents per year at intersections with…
The summary statistics are n=85, x=3.93, s=0.63. Use a 0.01 significance level to test the claim that the population of student course evaluations has a mean equal to 4.00. identify null/ alt hypothesis, test statistic, P- value, and state final conclusion that addresses the original claim
Explain, using a complete sentence, why we use the Standard Error (rather than the Standard Deviation) to estimate the population proportion or mean in a confidence interval.
Consider the sample dataset : 2,4,5,9,10. What is point estimate and sample standard deviation? What is margin of error at 95% confidence level? Calculate confidence intervals at 95% confidence level.
n a survey, 23 people were asked how much they spent on their child's last birthday gift. The results were roughly bell-shaped with a mean of $31 and standard deviation of $17. Construct a confidence interval at a 95% confidence level.Give your answers to one decimal place. +-Interpret your confidence interval in the context of this problem.

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