A simple random sample of size n is drawn from a population that is normally distributed. The sample mean, x, is found to be 115, and the sample standard deviation, s, is found to be 10.(a) Construct a 96% confidence interval about μ if the sample size, n, is 15.(b) Construct a 96% confidence interval about μ if the sample size, n, is 11.(c) Construct an 80% confidence interval about u if the sample size, n, is 15.(d) Could we have computed the confidence intervals in parts (a)-(c) if the population had not been normally distributed?Click the icon to view the table of areas under the t-distribution. A survey was conducted that asked 1011 people how many books they had read in the past year. Results indicated that x = 14.8 books and s= 16.6 books. Construct a 90% confidence interval for the mean number of books people read. Interpret the interval.Click the icon to view the table of critical t-values.Construct a 90% confidence interval for the mean number of books people read and interpret the result. Select the correct choice below and fill in the answer boxes to complete your choice.(Use ascending order. Round to two decimal places as needed.)OA. There is 90% confidence that the population mean number of books read is between andB. If repeated samples are taken, 90% of them will have a sample mean betweenO C. There is a 90% probability that the true mean number of books read is betweenandand

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MATLAB: An Introduction with Applications

6th Edition

ISBN:9781119256830

Author:Amos Gilat

Publisher:Amos Gilat

Chapter1: Starting With Matlab

Section: Chapter Questions

Problem 1P

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The law of large numbers states that as the number of observations drawn at random from a population with finite mean increases, the mean of the observed values: a. tends to get closer and closer to the population mean . b. gets smaller and smaller. c. gets larger and larger. d. fluctuates steadily between 1 standard deviation above and 1 standard deviation below the mean. I collect a random sample of size n from a population and compute a 95% confidence interval for the proportion I observe from the population. What could I do to produce a new confidence interval with a larger width (larger margin of error) based on these same data? a. I could use the same confidence level but compute the interval n times; approximately 5% of these intervals will be larger. b. Nothing can guarantee absolutely that I will get a larger interval; I can only say the chance of obtaining a larger interval is 0.05. c. I could use a smaller confidence…
A simple random sample of size n is drawn from a population that is normally distributed. The sample mean, x, is found to be 19.6, and the sample standard deviation, s, is found to be 5.6. (a) Construct a 98% confidence interval about u if the sample size, n, is 32. (b) Construct a 98% confidence interval about µ if the sample size, n, is 58. How does increasing the sample size affect the margin of error, E? (c) Construct a 99% confidence interval about u if the sample size, n, is 32. How does increasing the level of confidence affect the size of the margin of error, E? (d) If the sample size is 21, what conditions must be satisfied to compute the confidence interval? (a) Construct a 98% confidence interval about µ if the sample size, n, is 32. Lower bound:; Upper bound: (Round to two decimal places as needed.) C...
A simple random sample of size n is drawn from a population that is normally distributed. The sample mean, x, is found to be 115, and the sample standard deviation, s, is found to be 10. (a) Construct an 80% confidence interval about μ if the sample size, n, is 25. (b) Construct an 80% confidence interval about μ if the sample size, n, is 12. (c) Construct a 70% confidence interval about μ if the sample size, n, is 25. (d) Could we have computed the confidence intervals in parts (a)-(c) if the population had not been normally distributed?
A simple random sample of size n=40 is drawn from a population. The sample mean is found to be x=120.1 and the sample standard deviation is found to be s=13.2. Construct a 99% confidence interval for the population mean. The lower bound is (Round to two decimal places as needed.)
A simple random sample of size n is drawn from a population that is normally distributed. The sample mean, x, is found to be 108, and the sample standard deviation, s, is found to be 10. (a) Construct a 98% confidence interval about μ if the sample size, n, is 16. (b) Construct a 98% confidence interval about µ if the sample size, n, is 12. (c) Construct a 70% confidence interval about u if the sample size, n, is 16. (d) Could we have computed the confidence intervals in parts (a)-(c) if the population had not been normally distributed? Click the icon to view the table of areas under the t-distribution. (a) Construct a 98% confidence interval about μ if the sample size, n, is 16. Lower bound:; Upper bound: (Use ascending order. Round to one decimal place as needed.)
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A simple random sample with n= 52 provided a sample mean of 23.0 and a sample standard deviation of 4.3. a. Develop a 90% confidence interval for the population mean (to 1 decimal). b. Develop a 95% confidence interval for the population mean (to 1 decimal). c. Develop a 99% confidence interval for the population mean (to 1 decimal). d. What happens to the margin of error and the confidence interval as the confidence level is increased? - Select your answer -
A simple random sample of size n is drawn from a population that is normally distributed. The sample mean, x, is found to be 109, and the sample standard deviation, s, is found to be 10. (a) Construct a 95% confidence interval about if the sample size, n, is 14. (b) Construct a 95% confidence interval about if the sample size, n, is 18. H (c) Construct a 99% confidence interval about u if the sample size, n, is 14. (d) Could we have computed the confidence intervals in parts (a)-(c) if the population had not been normally distributed? Lower bound: Upper bound: (Use ascending order. Round to one decimal place as needed.) COLL Save
A simple random sample of size n is drawn from a population that is normally distributed. The sample mean, x, is found to be 108, and the sample standard deviation, s, is found to be 10. (a) Construct a 96% confidence interval about µ if the sample size, n, is 13. (b) Construct a 96% confidence interval about µ if the sample size, n, is 29. (c) Construct a 99% confidence interval about μ if the sample size, n, is 13. (d) Could we have computed the confidence intervals in parts (a)-(c) if the population had not been normally distributed? FClick the icon to view the table of areas under the t-distribution. (a) Construct a 96% confidence interval about μ if the sample size, n, is 13. Lower bound: Upper bound: (Use ascending order. Round to one decimal place as needed.)

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