A simple random sample of size n is drawn from a population that is normally distributed. The sample mean, \(\bar{x}\), is found to be 108, and the sample standard deviation, \(s\), is found to be 10.(a) Construct a 96% confidence interval about \(\mu\) if the sample size, \(n\), is 13.(b) Construct a 96% confidence interval about \(\mu\) if the sample size, \(n\), is 29.(c) Construct a 99% confidence interval about \(\mu\) if the sample size, \(n\), is 13.(d) Could we have computed the confidence intervals in parts (a)-(c) if the population had not been normally distributed?Click the icon to view the table of areas under the t-distribution.---(a) Construct a 96% confidence interval about \(\mu\) if the sample size, \(n\), is 13.Lower bound: [Input field] Upper bound: [Input field](Use ascending order. Round to one decimal place as needed.)

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MATLAB: An Introduction with Applications

6th Edition

ISBN:9781119256830

Author:Amos Gilat

Publisher:Amos Gilat

Chapter1: Starting With Matlab

Section: Chapter Questions

Problem 1P

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Suppose scores on exams in statistics are normally distributed with an unknown population mean and a population standard deviation of three points. A random sample of 36 scores is taken and gives a sample mean (sample mean score) of 68. Find a 90% confidence interval for the true (population) mean of statistics exam scores. a. Step 1: Find the critical value for the 90% confidence interval. b. Step 2: Calculate the error bound EBM. c. Step 3: Construct a 90% confidence interval for the true population mean of statistics exam scores.
A simple random sample of size n=17 is drawn from a population that is normally distributed. The sample mean, x, is found to be 107, and the sample standard deviation, s, is found to be 10. Construct a 90% confidence interval about μ. The 90% confidence interval about μ is enter your response here to enter your response here. (Round to two decimal places as needed.)
A sample of size n = 36 is drawn from a population whose standard deviation is σ = 15.6. The sample mean is x = 94.5. Construct a 95% confidence interval.
A simple random sample of size n = 40 is drawn from a population. The sample mean is found to be x = 121.2 and the sample standard deviation is found to be s = 12.6. Construct a 99% confidence interval for the population mean. The lower bound is (Round to two decimal places as needed.) The upper bound is . (Round to two decimal places as needed.)
A simple random sample of size n is drawn from a population that is normally distributed. The sample mean, x, is found to be 108, and the sample standard deviation, s, is found to be 10. (a) Construct a 98% confidence interval about μ if the sample size, n, is 16. (b) Construct a 98% confidence interval about µ if the sample size, n, is 12. (c) Construct a 70% confidence interval about u if the sample size, n, is 16. (d) Could we have computed the confidence intervals in parts (a)-(c) if the population had not been normally distributed? Click the icon to view the table of areas under the t-distribution. (a) Construct a 98% confidence interval about μ if the sample size, n, is 16. Lower bound:; Upper bound: (Use ascending order. Round to one decimal place as needed.)
A simple random sample of size n is drawn from a population that is normally distributed. The sample mean,x, is found to be 112, and the sample standard deviation, s, is found to be 10. A. Construct a 98% confidence interval about μ if the sample size, n, is 18. Lower bound- Upper Bound- B. Construct a 98% confidence interval about μ if the sample size, n, is 28. Lower bound- Upper Bound- C. Construct a 99% confidence interval about μ if the sample size, n, is 18. Lower bound- Upper Bound-
A simple random sample of size n is drawn from a population that is normally distributed. The sample mean, x, is found to be 110, and the sample standard deviation, s, is found to be 10. (a) Construct a 98% confidence interval about μ if the sample size, n, is 15. (b) Construct a 98% confidence interval about μ if the sample size, n, is 24. (c) Construct a 99% confidence interval about μ if the sample size, n, is 15. (d) Could we have computed the confidence intervals in parts (a)-(c) if the population had not been normally distributed?
A sample of n = 7 scores is selected from a population with an unknown mean ( µ). The sample has a mean of M = 40 and a variance of s 2 = 63. Which of the following is the correct 95% confidence interval for µ?
9.- One of the most serious health problems in India is malaria. Consequently, Indian hospital administrators must have the resources to treat the high volume of malaria patients that are admitted. A research investigated whether the malaria admission rate is higher in some months than in others. In a sample of 192 hospital patients admitted in January, 32 were treated for malaria. In an independent sample of 403 patients admitted in May (4 months later), 34 were treated for malaria. a) Give point estimates for the malaria admission rates in January and in May. Answer: b) Find a 90% confidence interval for the difference in the malaria admission rates in January and May. Answer: c) Based on the above confidence interval, can you conclude that a difference exists in the true malaria admission rates in January and May? Answer:
Use the bootstrap distributions in Figure 1 to estimate the value of the sample statistic and standard error, and then use this information to give a 95 % confidence interval. In addition, give notation for the parameter being estimated. The bootstrap distribution in Figure 1, generated for a sample correlation to 0.25 0.30 0.35 0.40 0.45 0.50 0.55 Figure 1 Bootstrap distribution (a) Give the sample statistic for the parameter being estimated. Round your answer to one decimal place. Sample statistic = eTextbook and Media (b) Estimate the standard error. Round your answer to two decimal places. standard error = i eTextbook and Media (c) Give the 95 % confidence interval. Round your answers to two decimal places, if necessary. The 95 % confidence interval is i to i e Textbook and Media

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