-oup 1 2₁ = 13x₁=231.8=136.9 oup 22₂=25x₂=268.1=533.6 row gives the sample sizes, the second row gives the sample means, and the third row gives the sample variances.) of the ratio of the variances of these two populations. Then find the lower limit and upper limit of the 90% ta 90% confidence interval for ce interval. ur intermediate computations to at least three decimal places. Write your final responses to at least two decimal places. (If necessary, consult a list of -) r limit: r limit:
-oup 1 2₁ = 13x₁=231.8=136.9 oup 22₂=25x₂=268.1=533.6 row gives the sample sizes, the second row gives the sample means, and the third row gives the sample variances.) of the ratio of the variances of these two populations. Then find the lower limit and upper limit of the 90% ta 90% confidence interval for ce interval. ur intermediate computations to at least three decimal places. Write your final responses to at least two decimal places. (If necessary, consult a list of -) r limit: r limit:
MATLAB: An Introduction with Applications
6th Edition
ISBN:9781119256830
Author:Amos Gilat
Publisher:Amos Gilat
Chapter1: Starting With Matlab
Section: Chapter Questions
Problem 1P
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Transcribed Image Text:Random samples are drawn independently from two normally distributed populations, and the following statistics are obtained.
Group 1 2₁ =
13x₁=231.8=136.9
Group 2 ₂ =25x₂=268.12=533.6
(The first row gives the sample sizes, the second row gives the sample means, and the third row gives the sample variances.)
Construct a 90% confidence interval for the ratio of the variances of these two populations. Then find the lower limit and upper limit of the 90%
3
03
confidence interval.
Carry your intermediate computations to at least three decimal places. Write your final responses to at least two decimal places. (If necessary, consult a list of
formulas.)
Lower limit:
Upper limit:
Ś
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