Find the electrostatic potential difference between points B and C (V(B)-V(C)=?) region that is being generated due to the Q=-3 C load homogeneously distributed on the insulating shell with radius R=a and Q = +4 C load homogeneously distributed on the insulating shell with radius R=b given in the figure. C(3,3,3) B(2,2,2) b
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Q: 1 -02 - 4 3
A: Given: Electric field=E=52.5 NC Distance=d=0.245 m Angle=θ=46.4°
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- EP-2 Equipotential lines for part of a charge distribution are shown to the right. The grid on which the lines are shown measures 1cm by 1cm. 1cm 1cm a) Circle the region on the grid where the electric field strength is greatest and calculate the strength of the field in this region. 2V \4V 6V 8V 10V b) Circle the region on the grid where the electric field strength is least and calculate the strength of the field in this region. c) Sketch 8 electric field lines starting at the center of the 2V circle. Be sure to put an arrowhead on each line. What is the sign of the charge at the center of the 2V circle?A spherical conductor has a radius of 14.0 cm and a charge of 52.0 µC. Calculate the electric field and the electric potential at the following distances from the center.A small positive test charge of 0.02C is situated 1.5m away from a positive charge of 1C and 4.2m away from a second positive charge of 14C. What is the total potential energy of the test charge. The coulomb constant K = 9E9. Give your answer in GigaJoules (GJ)
- A Q load is placed at each of the opposite vertices of a square. Another q load is placed at each of the other two vertices of the square. A) If the resulting force over Q is zero, what is the ratio (Q/q), between Q and q loads? B) Calculate the electrical potential at each of the midpoints on the sides of the square. The side of the square is 10 cm and Q is +20uc.Two identical balls each having a density p are suspended from a common point by two insulating strings of equal length. Both the balls have equal mass and charge. In equilibrium, each string makes an angle with the vertical. Now, both the balls are immersed in a liquid. As a result, the angle does not change. The density of liquid is o. Find the dielectric constant of the liquid.The electric field in a region of space is E? = 5000x [V/m] where x is in meters. a) Graph Ex vs x over the region -1 [m] ≤ x ≤ 1 [m].b) Find an expression for the potential V at position x, let ? = 0 at the origin.c) Graph V vs x over the region -1 [m] ≤ x ≤ 1 [m]
- A particle carrying charge +g is located on the z axis at z=+d. A particle carrying charge-3g is located on the z axis at z=-7d ▸ Part A ▸ ▸ ▾ ▼ Part B Part C Part D At what location on the yaxis with positive coordinate is the potential zera? Express your answer in terms of d. y = Submit Part E O yes O no ROBERSY DE ΓΙ ΑΣΦ 5 Submit Request Answer Are there any locations on the zor y axis where the electrostatic potential is zero for the case where the object at z= 7d carries charge +37 Provide Feedback Ĉ Request Answer ? Next >Two parallel plates have equal and opposite charges. When the space between the plates is evacuated, the electric field is E= 3.30×105 V/m. When the space is filled with dielectric, the electric field is E= 2.50×105 V/m. For related problem-solving tips and strategies, you may want to view a Video Tutor Solution of Energy density, both before and after the. What is the charge density on each surface of the dielectric? Express your answer in coulombs per meter squared. να ΑΣΦ ? |X| X•10" |oi| = C/m²Part A Near the surface of the Earth there is an electric field of about 150 V/m which points downward. Two identical balls with mass 0.467 kg are dropped from a height of 2.37 m, but one of the balls is positively charged with g = 412 µC , and the second is negatively charged with q2=-412 µC. Use conservation of energy to determine the difference in the speeds of the two balls when they hit the ground. (Neglect air resistance.) Express your answer using three significant figures. V AEO ? V4 -v_ = m/s Submit Request Answer
- 23.131.25 points An electric field in a region of space is parallel to the x- axis. The electric potential varies with position as shown in the figure. Find the magnitude of the electric field (in kV/m) at x-2.5 cm. 50 40 30 20 10 x (cm) -10 -20 -30 -40 -50 ३ दि २०१३३३६Points B [at (4,-5) m] and C [at (3, 5) m] are in a region where the electric field is uniform and given by E=-5i-+4j N/C. What is the potential difference VC- VB? (10 points