Two conducting plates of equal area A are separated by a distance d by forming a parallel plate capacitor. When a potential difference of V is applied across the capacitor, a charge with magnitude Q is observed on the plates of the capacitor. a)If the potential difference across the capacitor is V= 2000 V and the magnitude of the charge on the plates of the capacitor is Q= 3460 µC, calculate the capacitance of this capacitor.
Dielectric Constant Of Water
Water constitutes about 70% of earth. Some important distinguishing properties of water are high molar concentration, small dissociation constant and high dielectric constant.
Electrostatic Potential and Capacitance
An electrostatic force is a force caused by stationary electric charges /fields. The electrostatic force is caused by the transfer of electrons in conducting materials. Coulomb’s law determines the amount of force between two stationary, charged particles. The electric force is the force which acts between two stationary charges. It is also called Coulomb force.
Two
a)If the potential difference across the capacitor is V= 2000 V and the magnitude of the charge on the plates of the capacitor is Q= 3460 µC, calculate the capacitance of this capacitor.
Trending now
This is a popular solution!
Step by step
Solved in 2 steps with 2 images
