EP-2 Equipotential lines for part of a charge distribution are shown to the right. The grid on which the lines are shown measures 1cm by 1cm 1cm/ 1cm. a) Circle the region on the grid where the electric field strength is greatest and calculate the strength of the field in this region. 2V \4V 6V 8V 10V b) Circle the region on the grid where the electric field strength is least and calculate the strength of the field in this region. c) Sketch 8 electric field lines starting at the center of the 2V circle. Be sure to put an arrowhead on each line. What is the sign of the charge at the center of the 2V circle?
a) electric field is the greatest in the 2V region.
assuming that voltage is zero at the centre of this region, it only takes appx. 0.5 cm to go to 2 volts.
The electric field strength can be calculated as
| E |= change in voltage/ change in distance = ( 2-0)/(0.005-0) = 400 v/m
b) The least strength of field is between 8 and 10 V region i.e. outmost region.
| E | = (10 - 8 )/ (0.025) = 80 V/m
these are appx. values.
c) To draw field lines, just join the centre of the 2V region to the 10 V circle with as many straight lines as you can and the arrowheads should be pointing towards the centre.
it also confirms a and b part, as the field lines density is greatest in the 2V region making the field strength highest here and vice versa for the 10 V region.
The charge inside the 2V region is of negative polarity as field lines are converging here and their arrowheads always point toward -ve charges.
Trending now
This is a popular solution!
Step by step
Solved in 2 steps with 1 images
