Find RL in the network above in order to achieve maximum power transfer. Take 10V, R₁ =6k, R₂ = 12k, R3 = 9kQ and RA R1 = = 12kN. V₁ = RL The open 6.24 ΚΩ circuit voltage (with R removed) is The power dissipated in the load resistor is PL V. mW. R₁ R₂ R3 R4 RL

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