a) When a capacuitr is connected to a DC Source for a long time it acts i= V = 4+222 as open ciruit, hence hore current 1:2V 262 = 0-04615 A Vc ac. 1-2V 22 now P= i?R= 0-04615(4} = 8:52 mW as capacitor is conmeced aows 222 revistor, hence Vc = i·22 = 6 -046 15 )(22)= 1· DI54 V b) In second case alo, the capacitor wlagain be short ciruuit due to DC vource, hence current will not flow. i = O A P4on= ow, Pzza=oW O-C 222 402 1-2V Vc = Vin= 1-2Vr. (bykvL)
a) When a capacuitr is connected to a DC Source for a long time it acts i= V = 4+222 as open ciruit, hence hore current 1:2V 262 = 0-04615 A Vc ac. 1-2V 22 now P= i?R= 0-04615(4} = 8:52 mW as capacitor is conmeced aows 222 revistor, hence Vc = i·22 = 6 -046 15 )(22)= 1· DI54 V b) In second case alo, the capacitor wlagain be short ciruuit due to DC vource, hence current will not flow. i = O A P4on= ow, Pzza=oW O-C 222 402 1-2V Vc = Vin= 1-2Vr. (bykvL)
Introductory Circuit Analysis (13th Edition)
13th Edition
ISBN:9780133923605
Author:Robert L. Boylestad
Publisher:Robert L. Boylestad
Chapter1: Introduction
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apply all methods to slove. Show KCL for each

Transcribed Image Text:a)
When a capacity is connected to a DC Source for a long time
it acts
as open ciruit, henu here current
i=V=
4+222
12V = 0-04615 A
Vc ac.
1-2V
22n
262
now P= i?R= (D-046152(4} = 8.52 mW
as capacitor is conmeced aowrs 222 reniter, hence
Vc = i·22 = (6.04615 )(22)= l· D154 V
(9
In second case also, the capacitor willagan be short ciruit due sto
DC vwrce, ħence current will not flow.
i = O A
P4on= Ow, Pzza=oW
Vc = Vin= 1:2V. (bykvL)
O-C
222
402
1:2V
%3D
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