Find and interpret the p-value for this test.
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Q: as long been stated that the mean temperature of humans is 98.6°F. However, two researchers…
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Q: c. Find the P-value. P-value = (Round to four decimal places as.needed.)
A: The degrees of freedom is, df=n-1=49-1=48 The degrees of freedom is 48.
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Q: A simple random sample of 36 men from a normally distributed population results in a standard…
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A: The hypothesized population mean is 70.
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A: Hey there! Thank you for posting the question. Since your question has more than 3 parts, we are…
Q: The average number of accidents at controlled intersections per year is 5.8. Is this average less…
A: Given, The average number of accidents at controlled intersections per year is 5.8. Is this average…
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A: Ho:u=3.15 vs H1: u<3.15 xbar=3.10, n=50, σ=0.15
Q: A Simple random sample of 35 men from a normally distributed population results in a standard…
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Q: Scores on a certain “IQ" test for 18-25 year olds are normally distributed. A researcher believes…
A: Given We have given p-value = 0.337 and level of significance α=0.05
Q: You wish to test Ho: μ = 87.5 versus Ha: 87.5 at a significance level of 0.10. You obtain a sample…
A: (a) The hypothesis test is; H0: μ=87.5vs Ha: μ≠87.5significance level(α) = 0.10sample size(n) =…
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A: Followings are the Explanation of the question Use the one sample t test Given that, Hypothesized…
In a test of the hypothesis
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observations possessed
and standard deviation
Find and interpret the p-value for this test.
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- A simple random sample of 37 men from a normally distributed population results in a standard deviation of 11.4 beats per minute. The normal range of pulse rates of adults is typically given as 60 to 100 beats per minute. If the range rule of thumb is applied to that normal range, the result is a standard deviation of 10 beats per minute. Use the sample results with a 0.10 significance level to test the claim that pulse rates of men have a standard deviation equal to 10 beats per minute. Complete parts (a) through (d) below. a. Identify the null and alternative hypotheses. Choose the correct answer below. O A. Ho: 0= 10 beats per minute O B. Ho: 0± 10 beats per minute H,: 0+ 10 beats per minute H,: 0= 10 beats per minute O C. Ho: o2 10 beats per minute H1: o< 10 beats per minute O D. Ho: 0 = 10 beats per minute H: o<10 beats per minuteIt has long been stated that the mean temperature of humans is 98.6°F. However, two researchers currently involved in the subject thought that the mean temperature of humans is less than 98.6°F. They measured the temperatures of 50 healthy adults 1 to 4 times daily for 3 days, obtaining 225 measurements. The sample data resulted in a sample mean of 98.4°F and a sample standard deviation of 1°F. Use the P-value approach to conduct a hypothesis test to judge whether the mean temperature of humans is less than 98.6°F at the oa = 0.01 level of significance. State the hypotheses. Ho: H = 98.6°F H1: H < 98.6°F Find the test statistic. tn = - 3.00 (Round to two decimal places as needed.) The P-value is (Round to three decimal places as needed.)A simple random sample of 101 course evaluations had a mean x¯x¯ = 3.90 with a standard deviation s = 0.52. Use a 0.05 significance level to test the claim that the population of course evaluations has a mean less than 4.00.
- 1) Your instructor tells you that past average scores for the final exam are 75%. But this semester he has been using online quizzes to help your class better prepare for the final. Your class scored the following on the final exam: mean= 80% with a 10% standard deviation. There are 49 people in your class. Using a one-sample t test, what is your t score for this class? Assuming α = .05, did the online quizzes help your class perform better?Scores on a certain "IQ" test for 18-25 year olds are normally distributed. A researcher believes that the average IQ score for students at a certain NJ college is less than 110 points, and so wants to test this hypothesis. The researcher obtain a SRS of 45 student IQ scores from school records and found the mean of the 45 results was 108 with a sample standard deviation of 21. The level of significance (alpha) used for this problem is 0.05. What is the appropriate test statistic (Student must complete by showing by formula using the ap- propriate values in that formula "showing work" and the final answer and appropriate label)? O T test score = (108-110)/(21/sqrt(45)) = -.639 T test score (108-110)/(21/sqrt(45)) = .639 %3D OT test score = (110-108)/(21/sqrt(45)) = .639 %3D T test score (108-110)/(45/sqrt(21)) =-.2037 %3D 素A simple random sample of 36 men from a normally distributed population results in a standard deviation of 12.8 beats per minute. The normal range of pulse rates of adults is typically given as 60 to 100 beats per minute. If the range rule of thumb is applied to that normal range, the result is a standard deviation of 10 beats per minute. Use the sample results with a 0.10 significance level to test the claim that pulse rates of men have a standard deviation equal to 10 beats per minute. Complete parts (a) through (d) below.Question content area bottomPart 1a. Identify the null and alternative hypotheses. Choose the correct answer below.A.H0: σ=10 beats per minuteH1: σ≠10 beats per minuteB.H0: σ≠10 beats per minuteH1: σ=10 beats per minuteC.H0: σ≥10 beats per minuteH1: σ<10 beats per minuteD.H0: σ=10 beats per minuteH1: σ<10 beats per minutePart 2b. Compute the test statistic.χ2=enter your response here (Round to three decimal places as needed.)Part 3c. Find the…
- A simple random sample of 36 men from a normally distributed population results in a standard deviation of 11.8 beats per minute. The normal range of pulse rates of adults is typically given as 60 to 100 beats per minute. If the range rule of thumb is applied to that normal range, the result is a standard deviation of 10 beats per minute. Use the sample results with a 0.10 significance level to test the claim that pulse rates of men have a standard deviation equal to 10 beats per minute. Complete parts (a) through (d) below. a. Identify the null and alternative hypotheses. Choose the correct answer below. A. H0: σ≥10 beats per minute H1: σ<10 beats per minute B. H0: σ≠10 beats per minute H1: σ=10 beats per minute C. H0: σ=10 beats per minute H1: σ≠10 beats per minute D. H0: σ=10 beats per minute H1: σ<10 beats per minute b. Compute the test statistic. χ2=48.73448.734 (Round to three decimal places as needed.) c. Find…A simple random sample of 25 filtered 100 mm cigarettes is obtained, and the tar content of each cigarette is measured. The sample has a mean of 19.8 mg and a standard deviation of 3.18 mg. Use a 0.05 significance level to test the claim that the mean tar content of filtered 100 mm cigarettes is less than 21.1 mg, which is the mean for unfiltered king size cigarettes. What do the results suggest, if anything, about the effectiveness of the filters?A simple random sample of 46 men from a normally distributed population results in a standard deviation of 9.6 beats per minute. The normal range of pulse rates of adults is typically given as 60 to 100 beats per minute. If the range rule of thumb is applied to that normal range, the result is a standard deviation of 10 beats per minute. Use the sample results with a 0.10 significance level to test the claim that pulse rates of men have a standard deviation equal to 10 beats per minute. Complete parts (a) through (d) below.
- The average test score at a university is 78 with a standard deviation of 5. A professor believes the average test score of students in his class is different form 78. If a sample of 102 students was selected with a sample mean score of 79.1 and our level of significance is set at .05: What is the standard error of the mean? What is the calculated test statistic (zobt). Compute effect size using Cohen’s dMedical research has shown that repeated wrist extension beyond 20 degrees increases the risk of wrist and hand injuries. Each of 24 students at a university used a proposed new computer mouse design, and while using the mouse, each student's wrist extension was recorded. Data consistent with summary values given in a paper are shown. Use these data with the resulting sample mean 25.750000 and sample standard deviation 1.870829, to test the hypothesis that the mean wrist extension for people using this new mouse design is greater than 20 degrees. (Use x = 0.05.) 27 22 OH₂ μ = 20 Hà U = 20 Ho: μ = 20 H₂ μ 20 State the appropriate null and alternative hypotheses. Ο Μ μ 20 ⒸH: μ> 20 Hàu<20 25 24 P-value = 26 26 28 27 25 27 24 28 24 31 26 26 26 24 25 24 25 27 27 24 Find the test statistic and P-value. (Round your test statistic to one decimal place and your P-value to three decimal places.) t = State your conclusion. O We reject Ho. We do not have convincing evidence that the mean wrist…In testing the difference between two population means using two independent samples, the population standard deviations are assumed to be known, and the calculated test statistic equals 2.75. If the test is two-tail and 5% level of significance has been specified, the conclusion should not be reject the null hypothesis. Select one: True False