This question considers a hypothesis test with H0: μ = 200 and H1: μ ≠200 and significance level 5%. A random sample of 25 taken from a population has mean value 224 and standard deviation 50. Should the null hypothesis be rejected?
Q: Need P-Value, Decision on the Null hypothesis, and Interpret the Result, answered thank you.
A:
Q: Suppose a researcher is testing the hypothesis Ho: p=0.4 versus H₁ p>0.4 and she finds the P-value…
A: P-value = 0.25
Q: A hypothesis test procedure uses paired samples to compare the mean paired difference of a…
A: The difference is taken as before –after. The hypotheses to be tested are: Null hypothesis: H0: μ1-…
Q: Exhibit 13-12 SSTR = SSE = 900 nT= 18 .22 736 Refer to Exhibit 13-12. The test statistic to test the…
A: The values given in the question are as : Sum of square for treatments (SSTR) = 736 Sum of square…
Q: Given two independent random samples with the following results: n₁ = 651 x₁ = 307 n₂ = 569 x2 = 234…
A: There are two independent samples which are population 1 and population 2.We have to test whether…
Q: mean score for the most recent applicants is lower than 70. He randomly samples the scores of 10…
A:
Q: The statistic was calculated and reported as 12.98. Using a = .05, should the null hypothesis be…
A: Here the two categorical variables are college student status and voting behavior. Given that,…
Q: Assume that ?̅1 =100, ?̅2 =115, ?1 =19, ?2 =16, ?1 =50, and ?2 =40. Find a 95% confidence interval…
A: There are two independent variables which follows normal distribution. We have to construct 95%…
Q: The critical z-value for an 85% two tailed hypothesis test is a. 0.8023 b. 1.44 c. 1.04 d.…
A: For two tailed test we use critical z value at α2 Since here α=15% Therefore here we calculate…
Q: 3) A facilities manager at a university reads in a research report that the mean amount of time…
A: It is given that:
Q: It has been claimed that 71% of all adults use their cell phones within an hour of going to bed.…
A: From the provided information, The claim is that 71% of all adults use their cell phones within an…
Q: According to a survey, the average age at which American men get married is 30. To test if men in…
A: Given information- Sample size, n = 16 Sample mean, x-bar = 28.3 Sample standard deviation, s = 1.3…
Q: A genetic experiment involving peas yielded one sample of offspring consisting of 450 green peas and…
A: Let p is defined as the proportion of offspring peas will be yellow. The claim of the test is 25% of…
Q: A magazine reported that at the top 50 business schools in a region, students studied an average of…
A: Given dataA magazine reported that at the top 50 business schools in a regionstudents studied an…
Q: Russell says he is willing to accept a 5% chance of making a Type I error in this study. What is the…
A: Russell says he is willing to accept a 5% chance of making a Type I error in this study. so…
Q: population standard deviation is 0.6 are given. Ho: 27.1, H₁: p<7.1 and a significance level is…
A:
Q: A SRS of 18 statistics examinations was taken from a large normal population. The average score in…
A: The hypothesized population mean is 70.
Q: A survey of two local communities is conducted to see whether there is difference in the mean…
A: As per Bartleby guidelines , we are allowed to answer three sub parts. Thanks Since Both the…
Q: A sociologist develops a test to measure attitudes towards public transportation, and n = 27…
A: The sample size n is 27.
Q: A researcher wants to test to see if a population mean is different from 6. Based on a sample of…
A:
Q: As of 2012, the proportion of students who use a MacBook as their primary computer is 0.31. You…
A:
Q: A random sample of 25 statistics examinations was selected. The average score in the sample was 77…
A: Sample size (n) = 25 Mean x̅ = 77 Sample variance s2 = 169 So, standard deviation (s) = 13…
Q: In the test of hypothesis ?0:?=100 vs ??:?≠100. A sample of size 200 yields the standard test…
A: From the provided information, Sample size (n) = 200 The hypotheses are as follow: H0: µ = 100 Ha: µ…
Q: For a one-sample t-test, if other factors are held constant, which set of sample characteristics is…
A: Given that μ = 100
Q: major research study concluded that the mean number of times that adolescents had engaged in…
A: Given that We have to test hypothesis for the claim that that the true population mean less than…
Q: If the obtained sample mean has a z score of 1.69 and if a = .05, should you reject or fail to…
A: The given z-score is 1.69 and the alpha is 0.05.
Q: A researcher wants to check the claim that a certain species of reptile spend an average of 18.9…
A: Given that, Sample size n=29 Sample mean x¯=18 Sample standard deviation s=3
Q: A study was done using a treatment group and a placebo group. The results are shown in the table.…
A: To test the whether the two samples are from populations with the same mean, the null and…
Q: When 45 people used a certain diet for one year, their weight losses had a standard deviation of 4.8…
A: From the provided information, Sample size (n) = 45 Sample standard deviation (s) = 4.8
Q: A sample of 36 observations is selected from a normal population. The sample mean is 49, and the…
A: Sample size is n = 36 Sample mean = 49 Population SD = 5 Level of significance = .05 Test is that…
Q: nsulation workers. Twenty-six cancer deaths were observed in a cohort of 556 insulation workers.…
A: State the hypotheses.
Q: In order to monitor safety levels, scientists take samples of 7 randomly selected batches to test…
A: Let X represent the measurement for 7 randomly selected sample is given. .87, .75, .84, .83, .90,…
Q: A scientist predicts engineers are more creative than physicians. On a standard creativity test, the…
A:
Q: It is claimed that a car is driven on the average is no more than 20,000 kilometers per year. To…
A: Solution-: Given: x¯=23500,μ0=20000,n=100,s=3900,α=0.05 We select an appropriate statistical test…
This question considers a hypothesis test with H0: μ = 200 and H1: μ ≠200 and significance level 5%.
A random sample of 25 taken from a population has
Should the null hypothesis be rejected?
Step by step
Solved in 2 steps with 1 images
- A recent study focused on the number of times men and women send a Twitter message in a day. The information is summarized here. Sample Size Sample Mean Population Standard Deviation Men 25 23 5 Women 30 28 10 At the 0.01 significance level, we ask if there is a difference in the mean number of times men and women send a Twitter message in a day. Assume that women are population 1 and men are population 2. What is the p-value for this hypothesis test? Multiple Choice 0.0500 0.0164 0.0001 0.0082A study was done using a treatment group and a placebo group. The results are shown in the table. Assume that the two samples are independent simple random samples selected from normally distributed populations, and do not assume that the population standard deviations n are equal. Complete parts (a) and (b) below. Use a 0.10 significance level for both parts. What are the null and alternative hypotheses? OA. Ho: H₁ H₂ H₁: Hy #H₂ OC. Ho: H₁ H₂2 H₁: Hy > H₂ (Round to two decimal places as needed.) The P-value is (Round to three decimal places as needed.) The test statistic, t, is ← OB. Ho: H₁A large international company with over 1.5 million employees wants to estimate how many of their employees have a cholesterol level that is higher than the recommended level. The company collects data from a random sample of employees and creates a 95% confidence interval for the population mean cholesterol level for all company employees. The upper bound of a 95% confidence interval for the population mean cholesterol level was 261.48, and the width of the same 95% confidence interval was 10.44. In this confidence interval, what is the sample mean (x bar) cholesterol level? Provide your answer as a number rounded to two decimal placesA test of sobriety involves measuring the subject's motor skills. Twenty randomly-selected sober subjects take the test and produce a mean score of 41.0 with a standard deviation of 3.7. At the 0.01 level of significance, test the claim that the true mean score for all sober subjects is equal to 35.0. Use the traditional method of testing hypotheses. The results for the test turn out to be: Ho: H = 35.0. H1:µ/35.0. Test statistic: t 7.252. Critical values: t = -2.861, 2.861. Reject Ho. There is sufficient evidence to warrant rejection of the claim that the mean is equal to 35.0. If a defense attorney argues the results are not valid because the sample size was too small, is his argument valid here? Yes, because the t-test is not as powerful as the z-test. No, because we rejected the null hypothesis. Yes, because we rejected the null hypothesis. O No, the sample size is never an issuc. O We need more information to answer.A sample of 100 observations from a normal population has a mean of 50 and a standard deviation of 10. The null hypothesis is that the population mean is equal to 48, and the alternative hypothesis is that the population mean is greater than 48. Using a significance level of 0.05, what is the decision and conclusion of the hypothesis test?An economist collects a simple random sample of 32 teacher's salaries in Cititon, and finds a mean of $67,000 and a standard deviation of $8,000. Is there enough evidence to conclude, at a significance of alpha= 0.05, that the mean salary of teachers in Cititon is different than $70,000? What is the test statistic? What is the null hypothesis? What conclusion do we draw? Do we reject the null hypothesis? What is/ are the critical value(s)? What is the alternative hypothesis? What is the p-value for the problem above?Given two independent random samples with the following results: n₁ = 651 x₁ = 307 n2 = 569 x2 = 234 Can it be concluded that there is a difference between the two population proportions? Use a significance level of a = 0.02 for the test. Copy Data Step 5 of 6: Determine the decision rule for rejecting the null hypothesis Ho. Round the numerical portion of your answer to two decimal places.You are a researcher verifying the claim that the average adult consumes 1.7 cups of coffee per day. The population standard deviation is 0.5 cups per day. You sample 30 adults and find the average is 1.85 cups per day. Test the claim above at the alpha = 0.05 significance level. What do you conclude about the number of cups of coffee that adults consume each day? Group of answer choices - You cannot reject the null hypothesis. Even though your sample indicated 1.85 cups, there still is not sufficient evidence to overturn the claim that adults consume 1.7 cups per day. - This is a borderline case where the test statistic and the critical values are the same. We can neither accept nor reject the null hypothesis in this case. - You reject the null hypothesis. With thirty people consuming 1.85 cups on average , there is sufficient evidence to overturn the claim that adults consume 1.7 cups per day.A quiz related to digital knowledge was conducted. The quiz had 10 questions and covered topics such as the purpose of browser cookies, phishing scams, and privacy policies. The survey was given to 50 people. The mean score is 4.1 with a standard deviation of 2.6. We want to know if the data provide evidence that the mean score in the population is lower than 5. We will use alpha = 0.05 to make our decision. What is the null hypothesis for this question? Group of answer choices a. The proportion of people who pass the test is 5. b. The mean test score of the population is 5. c. The mean test score of the 50 people who took the test is 5. d.The standard deviation is 2.6The coach of a very popular men’s basketball team claims that the average distance the fans travel to the campus to watch a game is 35 miles. The team members feel otherwise. A sample of 16 fans who travel to games was randomly selected and yielded a mean of M= 36 miles and s= 5 miles. Test the coach’s claim at the 5% (.05) level of significance. one-tailed or two-tailed test: State the hypotheses: df= tα or t value for the critical region = sM = t (test statistic)= Decision:Suppose the national average dollar amount for an automobile insurance claim is $670.543. You work for an agency in Michigan and you are interested in whether or not the state average is different from the national average. The hypotheses for this scenario are as follows: Null Hypothesis: μ = 670.543, Alternative Hypothesis: μ ≠ 670.543. A random sample of 27 claims shows an average amount of $668.645 with a standard deviation of $68.6867. What is the test statistic and p-value for this test? Question 8 options: 1) Test Statistic: -0.144, P-Value: 0.44345 2) Test Statistic: -0.144, P-Value: 0.5566 3) Test Statistic: -0.144, P-Value: 1.5566 4) Test Statistic: 0.144, P-Value: 0.8869 5) Test Statistic: -0.144, P-Value: 0.8869The College Board reports that the scores on the math SAT were normally distributed with a mean of 525. A random sample of 15 students at your high school had a mean of 550 and a sample standard deviation of 105. What values of the sample mean would lead to rejection of the null hypothesis at the 0.01 level of significance?SEE MORE QUESTIONS
