What are the null and alternate hypotheses (write in equation/inequality form)? What is the p-value and the result, i.e. reject or fail to reject H0?
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What are the null and alternate hypotheses (write in equation/inequality form)?
What is the p-value and the result, i.e. reject or fail to reject H0?
(Show your work/rationale and calculator commands/inputs as appropriate)
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- An engineer is comparing voltages for two types of batteries (K and Q) using a sample of 3939 type K batteries and a sample of 5757 type Q batteries. The mean voltage is measured as 8.558.55 for the type K batteries with a standard deviation of 0.6830.683, and the mean voltage is 8.828.82 for type Q batteries with a standard deviation of 0.7910.791. Conduct a hypothesis test for the conjecture that the mean voltage for these two types of batteries is different. Let μ1μ1 be the true mean voltage for type K batteries and μ2μ2 be the true mean voltage for type Q batteries. Use a 0.020.02 level of significance. Step 3 of 4 : Determine the decision rule for rejecting the null hypothesis H0H0. Round the numerical portion of your answer to two decimal placesA discount airline allows staff 36.0 minutes between flights to clean the aircraft interior. The aircraft workers union claims that that average time that it takes to this cleaning is more than 36.0 minutes. They want to carry out a hypothesis test. They take a random sample n = 40 flights and time how long it takes to carry out the cleaning. They find that the sample mean is 36.66 minutes and the sample standard deviation is 5.56 minutes. Calculate the test statistic for this test and enter your answer below. Give your answer to 2 decimal places.A sample mean is 137, sample size is 20, and population standard deviation is 14.2 are given. Ho: μ-132, H1: µ#132 and a significance level is 0.05. Use the P-value approach to test the hypothesis. O a. a. z = 2.57; P-value = 0.0101; reject null hypothesis b. z = 0.35; P-value = 0.7263; do not reject null hypothesis O c. z = 1.57; P-value = 0.0582; do not reject null hypothesis O d. z = 1.57; P-value = 0.1164; do not reject null hypothesis
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- A custodian wishes to compare two competing floor waxes to decide which one is best. He believes that the mean of WaxWin is not equal to the mean of WaxCo. In a random sample of 12 floors of WaxWin and 20 of WaxCo. WaxWin had a mean lifetime of 27.6 with a standard deviation of 8.8 and WaxCo had a mean lifetime of 20.3 with a standard deviation of 7.6. Perform a hypothesis test using a significance level of 0.01 to help him decide. Let WaxWin be sample 1 and WaxCo be sample 2 The correct hypotheses are: HA: P1 > µ2(claim) Ho: µ1 2 µ2 HA: µ1 < µ2(claim) Ho: µ1 = µ2 HA: H1 + H2(claim) Since the level of significance is 0.01 the critical value is 2.836 and -2.836 The test statistic is: (round to 3 places) The p-value is: (round to 3 places)A simple random sample of 17 different cereals is obtained, and the sugar content (in grams of sugar per gram of cereal) is measured for each cereal selected. Those amounts have a mean of 0.293 gram and a standard deviation of 0.165 gram. Use a 0.05 significance level to test the claim of a cereal lobbyist that the mean for all cereals is less than 0.31 gram. Formulate the null and alternative hypotheses. Choose the correct answer below. OA. Ho: μ = 0.31 Ha: μ>0.31 OC. Ho: μ<0.31 H₂: p=0.31 novamal O B. Ho: μ = 0.31 Ha₂: μ0.31 O D. Ho: μ= 0.31 Hg:μ <0.31Identify the IV and the scale of measurement; Identify the DV and the scale of measurement and for the IV – identify the number of levels; Identify null and alternative hypotheses, are they directional or non-directional? Assume that the distributions of the populations are approximately normal.
- A sample of 42 observations is selected from one population with a population standard deviation of 4.5. The sample mean is 100.5. A sample of 56 observations is selected from a second population with a population standard deviation of 3.8. The sample mean is 98.5. Conduct the following test of hypothesis using the 0.10 significance level. H₂ H₁ H₂ H₁ H₁ H₂ a. Is this a one-tailed or a two-tailed test? O One-tailed test O Two-tailed test b. State the decision rule. (Negative values should be indicated by a minus sign. Round your answers to 2 decimal places.) The decision rule is to reject H0 if z is the interval (The Woodcock-Johnson Cognitive Ability (WJCA) test indicates that the average score is 95. The same group of 12th grade students (n = 72) in Columbus are tested and the sample mean is 110.1 and the sample standard deviation is 15.2. Do the scores provide good evidence that the mean WJCA score of this population is greater than 95? State the null (H0) and alternative (Ha) hypotheses. 2. What are the confidence intervals for this data? 3. What is the value of the test statistic? 4. What is the p-value for this data? 5. What is your decision about the null hypothesis?: Reject Fail to Reject 6. Summarize the conclusion in the context of the problem.BIG Corporation advertises that its light bulbs have a mean lifetime, u, of 3000 hours. Suppose that we have reason to doubt this claim and decide to do a statistical test of the claim. We choose a random sample of light bulbs manufactured by BIG and find that the mean lifetime for this sample is 3160 hours and that the sample standard deviation of the lifetimes is 600 hours. Based on this information, answer the questions below. What are the null hypothesis (H.) and the alternative hypothesis (H,) that should be used for the test? Ho: u is ? H: u is ? In the context of this test, what is a Type I error? A Type I error is ? v the hypothesis that u is? when, in fact, u is ? Suppose that we decide to reject the null hypothesis. What sort of error might we be making? ?